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gulaghasi [49]
3 years ago
11

The pH at the midpoint in the titration of an acid with a base is A) equal to the pK of the corresponding base. B) equal to the

pK of the corresponding acid. C) equal to 14 minus the pK of the corresponding acid. D) equal to 14 plus the pK of the corresponding base. E) none of the above
Chemistry
1 answer:
iVinArrow [24]3 years ago
6 0

Answer:

The pH at the midpoint in the titration of an acid with a base is

A) equal to the pK of the corresponding base.

B) equal to the pK of the corresponding acid.

C) equal to 14 minus the pK of the corresponding acid.

D) equal to 14 plus the pK of the corresponding base.

E) none of the above

Explanation:

When a weak acid is titrated with a strong base, then a buffer solution is formed.

pH of a buffer solution can be calculated by using the formula:

pH=pKa+log\frac{[salt]}{[acid]}

Exactly at the mid point,

[conjugate base of the salt]=[acid]

So, log [salt]/[acid] =0

Hence, pH of the solution will be equal to pKa of the weak acid.

Answer is option B.

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A student takes a measured volume of 3.00 M HCl to prepare a 50.0 mL sample of 1.80 M HCI. What volume of 3.00 M HCI
frozen [14]

Answer:

30 mL VOLUME OF 3.0 M HCl SHOULD BE USED BY THE STUDENT TO MAKE A 1.80 M IN 50 mL OF HCl.

Explanation:

M1 = 3.00 M

M2 = 1.80 M

V2 = 50 .0 mL = 50 /1000 L = 0.05 L

V1 = unknown

In solving this question, we know that number of moles of a solution is equal to the molar concentration multiplied by the volume. To compare two samples, we equate both number of moles and substitute for the required component.

So we use the equation:

                                  M1 V1 = M2 V2

V1 = M2 V2 / M1

V2 = 1.80 * 0.05 / 3.0

V2 = 0.09 /3.0

V2 = 0.03 L or 30 mL

To prepare the sample of 1.80 M HCl in 50.0 mL from a 3.0 M HCl, 30 mL volume should be used.

5 0
3 years ago
Two or more atoms that share electrons equally make a?
Marat540 [252]
A covalent bond that forms a compound.
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For metalloids on the periodic table, how do the group number and the period number relate?
Studentka2010 [4]

Answer : The correct option is A.

Explanation :

Metalloid : Metaloids are the elements whose properties lie between the metals and non-metals.

There are six commonly elements which are boron, silicon, germanium, arsenic, antimony and tellurium. The rare elements are polonium and astatine.

The relation between the group number and period number of metalloid is that the lower the group number, the lower the period numbers and the metalloids are found in a diagonal moving down from left to right in the periodic table.

5 0
2 years ago
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Diano4ka-milaya [45]

Answer:

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Explanation:

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Scientists don't know the exact cause of these diseases. As the cause is not known, there is no exact way to prevent them. There is no cure for them, either. The treatment is focused on the management of symptoms.

This is why the third option is the correct one.

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