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Bond [772]
3 years ago
11

In the series circuit, if the potential difference across the battery is 20 V and the potential difference across R1 is 12 V, wh

at is the potential difference across R2
Physics
1 answer:
pishuonlain [190]3 years ago
7 0

Answer:

The correct answer is "8 V".

Explanation:

Given:

Potential difference across battery,

= 20 V

Potential difference across R1,

= 12 V

Now,

On applying the Kirchorff loop, we get

⇒ E-I_1R_1-I_2R_2=0

⇒ E-V_1-V_2=0

⇒ V_2=E-V_1

On putting values, we get

⇒      =20-12

⇒      = 8 \ V  

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Wear a helmet. Stay visible; use bike lights and/or wear bright clothes. Look and Signal; use hand signals to let drivers know where you're going, try to make eye contact with them and look before you go.

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An object of volume 0.0004m^3 and density 6000kg/m^3 is immersed inside a fluid of density 5000kg/m^3. The force exerted by the
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We have that the density of the fluid is

\rho_f=178.57  kg/m3

From the question we are told that

object of volume 0.0004m^3

density 6000kg/m^3

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Force F=0.7N

Generally the equation for the Force   is mathematically given as

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\rho_f=178.57  kg/m3

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3 years ago
A merry go round has rotational inertia (moment of inertia) of 73.0 kg/m^2 and is rotating at a constant speed of 30.0 rads./sec
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2 years ago
Does the area of contact effect the frictional force . explain?​
OlgaM077 [116]

Answer:

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3 years ago
Establishing a potential difference The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 10
Nezavi [6.7K]

Answer:

t = 23.9nS

Explanation:

given :

Area A= 10 cm by 2 cm => 2 x 10^-2m x 10 x 10^-2m

distance d= 1mm=> 0.001

resistor R= 975 ohm

Capacitance can be calculated through the following formula,

C = (ε0  x A )/d

C = (8.85 x 10^-12 x (2 x 10^-2 x 10 x 10^-2))/0.001

C = 17.7 x 10^-12    (pico 'p' = 10^-12)

C = 17.7pF

the voltage between two plates is related to time, There we use the following formula of the final voltage

Vc = Vx (1-e^-(t/CR))  

75 = 100 x (1-e^-(t/CR))

75/100 = (1-e^-(t/CR))

.75 = (1-e^-(t/CR))

.75 -1 = -e^-(t/CR)

-0.25 = -e^-(t/CR)  --->(cancelling out the negative sign)

e^-(t/CR) = 0.25

in order to remove the exponent, take logs on both sides  

-t/CR = ln (0.25)

t/CR = -ln(0.25)

t = -CR x ln (0.25)

t = -(17.7 x 10^-12 x 975) x (-1.38629)

t = 23.9 x 10^{-9  

t = 23.9ns

Thus, it took 23.9ns  for the potential difference between the deflection plates to reach 75 volts

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3 years ago
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