Answer:
d = 6.32 m
Explanation:
Given that,
The mass of a puck, m = 2 kg
It is pushed straight north with a constant force of 5N for 1.50 s and then let go.
We need to find the distance covered by the puck when move from rest in 2.25 s.
We know that,
F = ma
Let d is the distance moved in 2.25 s. Using second equation of motion,
So, it will move 6.32 m from rest in 2.25 seconds.
The moment of inertia of the flywheel is 2.63 kg-
It is given that,
The maximum energy stored on the flywheel is given as
E=3.7MJ= 3.7× J
Angular velocity of the flywheel is 16000 = 1675.51
So to find the moment of inertia of the flywheel. The energy of a flywheel in rotational kinematics is given by :
E =
By rearranging the equation:
I =
I = 2.63 kg-
Thus the moment of inertia of the flywheel is 2.63 kg-.
Learn more about moment of inertia here;
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