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Dmitrij [34]
1 year ago
12

1. Using the periodic table and your knowledge of patterns and trends on the table, which of the following elements is the best

conductor of electricity?
A. Titanium **

B. Silicon

C. Oxygen

D. Argon

2. Using the periodic table and your knowledge of patterns and trends on the table, which of the following elements is the most reactive?

A. Titanium **

B. Silicon

C. Oxygen

D. Argon

3. Using the periodic table and your knowledge of patterns and trends on the table, which of the following elements has the highest electronegativity?

A. Titanium

B. Silicon

C. Oxygen **

D. Argon
Chemistry
1 answer:
Annette [7]1 year ago
3 0

From the periodic table as well as the patterns and trends on the table, the correct option are:

  1. the best conductor of electricity is Titanium; option A
  2. the most reactive element is oxygen; option C
  3. the elements that has the highest electronegativity is oxygen; option C

<h3>What is the periodic trends in the periodic table?</h3>

Periodic trends in the periodic table refers to the variation in character which is observed in the periodic table as one moves across the periodic table from left to right across a period or down a group in the periodic table.

The periodic trend observed is that reactivity of metals increase down a group and from right to left across a period.

For non-metals,  reactivity of non-metals increase from down to top in a group and from left to right across a period across a period.

Considering the given questions;

1. From the periodic table as well as the patterns and trends on the table, the best conductor of electricity is Titanium since it is the only metal in the list.

2. The most reactive element is oxygen because it is a non-metal found to the top-left of the periodic table.

3. The elements that has the highest electronegativity is oxygen because it is a non-metal found to the top-left of the periodic table.

Learn more about periodic trends at: brainly.com/question/28161428

#SPJ1

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Please help Me I really need it
butalik [34]
Can you show the question that goes with those answer pls
7 0
2 years ago
The value of the solubility product constant for Ag2CO3 is 8.5 × 10‒12 and that of Ag2CrO4 is 1.1 × 10‒12. From this data, what
Lena [83]

Answer:

B) 7.7

Explanation:

For the reaction    Ag2CO3(s) + CrO42‒(aq) → Ag2CrO4(s) + CO32‒(aq)

Kc = (CO₃²⁻) / (CrO₄²⁻)

and the Ksp given are

Ag₂CO₃    ⇒  2 Ag⁺(aq) + CO₃²⁻(aq)    Ksp₁ = (Ag⁺)²(CO₃²⁻)  

Ag₂CrO₄   ⇒  2 Ag⁺(aq)+ CrO₄²⁻(aq)   Ksp₂ = (Ag⁺)²(CrO₄²⁻)

Where (...) indicate concentrations M

Notice if we divide the expressions for Ksp we get:

Ksp₁/Ksp₂ = (CO₃²⁻)  / (CrO₄²⁻) = 8.5 x 10⁻¹² / 1.1 x 10⁻¹² = 7.7

which is the desired answer.

7 0
3 years ago
Which group is likely to react with chlorine to form compounds in the form xcl?
Umnica [9.8K]
Group 1 elements since they have one outermost electron which they can give to chlorine which has 7 outermost electrons in order to form a stable compound.

Example 
Pottasium (K) + Chlorine (Cl) = Potassium Chloride (KCL)
4 0
3 years ago
When the paramagnetic [co(cn)6] 4– ion is oxidized to [co(cn)6] 3– , the ion becomes diamagnetic. however, when the paramagnetic
S_A_V [24]
Answer:  
Basically, paramagnetic and diamagnetic refer to the way a chemical species interacts with a magnetic field. More specifically, it refers to whether or not a chemical species has any unpaired electrons or not. 
 A diamagnetic species has no unpaired electrons, while a paramagnetic species has one or more unpaired electrons. 
 Now, I won't go into too much detail about crystal field theory in general, since I assume that you're familiar with it. 
 So, you're dealing with the hexafluorocobaltate(III) ion, [CoF6]3â’, and the hexacyanocobaltate(III) ion, [Co(CN)6]3â’. 
 You know that [CoF6]3â’ is paramagnetic and that [Co(CN)6]3â’ is diamagnetic, which means that you're going to have to determine why the former ion has unpaired electrons and the latter does not. 
 Both complex ions contain the cobalt(III) cation, Co3+, which has the following electron configuration 
  Co3+:1s22s22p63s23p63d6 
 For an isolated cobalt(III) cation, all these five 3d-orbitals are degenerate. The thing to remember now is that the position of the ligand on the spectrochemical series will determine how these d-orbtals will split. 
 More specifically, you can say that 
  a strong field ligand will produce a more significant splitting energy, Δ  a weak field ligand will produce a less significant splitting energy, Δ 
 Now, the spectrochemical series looks like this 
 http://chemedu.pu.edu.tw/genchem/delement/9.htmhttp://chemedu.pu.edu.tw/genchem/delement/9.htm 
 Notice that the cyanide ion, CNâ’, is higher on the spectrochemical series than the fluoride ion, Fâ’. This means that the cyanide ion ligands will cause a more significant energy gap between the eg and t2g orbitals when compared with the fluoride ion ligands. 
 http://wps.prenhall.com/wps/media/objects/3313/3393071/blb2405.htmlhttp://wps.prenhall.com/wps/media... 
 In the case of the hexafluorocobaltate(III) ion, the splitting energy is smaller than the electron pairing energy, and so it is energetically favorable to promote two electrons from the t2g orbitals to the eg orbitals → a high spin complex will be formed. 
 This will ensure that the hexafluorocobaltate(III) ion will have unpaired electrons, and thus be paramagnetic. 
 On the other hand, in the case of the hexacyanocobaltate(III) ion, the splitting energy is higher than the electron pairing energy, and so it is energetically favorable to pair up those four electrons in the t2g orbitals → a low spin complex is formed. 
 Since it has no unpaired electrons, the hexacyanocobaltate(III) ion will be diamagnetic.
6 0
3 years ago
What is the total number of ions in one formula unit of (NH4)2CO3?
Len [333]

There are 3  ions in one formula unit of (NH4)2CO3.

Ions present in  Ammonium carbonate.(NH4)2CO3

(NH4)2CO3 is called Ammonium carbonate. The formula indicates that in one mole of ammonium carbonate, There are

  • Two moles of ammonium ions,NH₄⁺ with valency of +1.
  • 1 mole of Carbonate ions  CO₃²⁻  with valency of -2.

When 1 mole of ammonium carbonate is dissolved in water it gives

(NH₄)₂CO₃   ₊  H₂O---->2NH₄⁺    ₊  CO₃²⁻

Ions present are 2NH₄⁺   and CO₃²⁻

Learn more on (NH4)2CO3 here:brainly.com/question/2272720

4 0
2 years ago
Read 2 more answers
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