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LekaFEV [45]
3 years ago
13

How many moles of copper are in 1.51 x 1024 Cu atoms?

Chemistry
1 answer:
kkurt [141]3 years ago
8 0
<h3>Answer:</h3>

2.51 mol Cu

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.51 × 10²⁴ atoms Cu

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 1.51 \cdot 10^{24} \ atoms \ Cu(\frac{1 \ mol \ Cu}{6.022 \cdot 10^{23} \ atoms \ Cu})
  2. Multiply/Divide:                  \displaystyle 2.50747 \ mol \ Cu

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2.50747 mol Cu ≈ 2.51 mol Cu

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When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from
IgorLugansk [536]

The question is incomplete, here is the complete question.

When a mixture of sulfur and metallic silver is heated, silver sulfide is produced. What mass of silver sulfide is produced from a mixture of 3.0g Ag and 3.0g S_8.

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Explanation : Given,

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Molar mass of S_8 = 256 g/mole

Molar mass of Ag_2S = 247.8 g/mole

First we have to calculate the moles of Ag and S_8.

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From the balanced reaction we conclude that

As, 16 mole of Ag react with 1 mole of S_8

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Now we have to calculate the moles of Ag_2S

From the reaction, we conclude that

As, 16 mole of Ag react to give 8 mole of Ag_2S

So, 0.0278 moles of Ag react to give \frac{0.0278}{16}\times 8=0.0139 moles of Ag_2S

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\text{ Mass of }Ag_2S=\text{ Moles of }Ag_2S\times \text{ Molar mass of }Ag_2S

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Therefore, the mass of silver sulfide is produced from a mixture is 3.44 grams.

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