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grigory [225]
3 years ago
12

What happens when you grow the same crop over and over again in the same field

Chemistry
1 answer:
irinina [24]3 years ago
6 0
Well there's a couple reasons why. First, the land itself can become “tired" and less fertile<span>. This is because the same type of </span>crop<span> planted repeatedly in the same area keeps draining the land of the same nutrients needed for that plant's growth. Pest can also plant their nest near the crop if the farmer continues to plant the same crop in the same place. 

Which is the reason why things such as "crop rotation" exist to keep things fresh, and prevent what I described above from happening.</span>
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5 0
3 years ago
Balance the following chemical equation by providing the correct coefficients.
sukhopar [10]

Answer:

2Na+2H2O→2NaOH+H2

Explanation:

I think this is it

7 0
2 years ago
Argon gas has a boiling point of -197 °C. Which of the following diagrams best represents the
Paha777 [63]

Answer:

(a)

Explanation:

Hello,

In this case, the temperature required to boil argon, it means, transform it from liquid to gas is -197 °C. In such a way, since the temperature inside the steel sphere is -190 °C, which is greater than the boiling point, we realize argon is gaseous, therefore, the molecules will be spread inside the sphere as they will be moving based on the kinetic theory of gases.

For that reason, answer is scheme (a).

Best regards.

6 0
3 years ago
HELP TIMED !!!!
Troyanec [42]
Hello there what is the question?

6 0
3 years ago
Read 2 more answers
What is the volume at stp of 720.0 ml of a gas collected at 20.0 °c and 3.00 atm pressure?
MArishka [77]
Combined gas law is 
       PV/T = K (constant)

P = Pressure
V = Volume
T = Temperature in Kelvin

For two situations, the combined gas law can be applied as,
     P₁V₁ / T₁ = P₂V₂ / T₂

P₁ = 3.00 atm                                     P₂ = standard pressure = 1 atm
V₁ = 720.0 mL                                    T₂ = standard temperature = 273 K
T₁ = (273 + 20) K = 293 K
  
By substituting,
 3.00 atm x 720.0 mL / 293 K = 1 atm x V₂ / 273 K
                                          V₂ = 2012.6 mL

hence the volume of gas at stp is 2012.6 mL
5 0
3 years ago
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