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Komok [63]
3 years ago
5

What is calcium when it is in it natural state solid liquid or gas?

Chemistry
1 answer:
viktelen [127]3 years ago
6 0
It is a solid in its natural state but it can be a liquid
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If a “universal solvent” could dissolve anything, what problems might you imagine that would cause in everyday life?
algol13
People call water a 'universal solvent' because it is capable of dissolving more<span> substances than any other liquid. I think</span> it could<span> can be a major problem if every substance was readily soluble by water or any solvent. If so, it would mean that there is nothing that could contain water if it was not completely saturated with another solute. All in all, t</span><span>he idea of a universal solvent would be just impossible to imagine.</span>
3 0
3 years ago
Chemistry!! Please help!!
cluponka [151]

Answer:

4.993 ×10⁻¹¹ J

Explanation:

The <em>nuclear binding energy</em> is the energy equivalent to the mass defect.

The <em>mass defect</em> is the difference between the mass of a nucleus and the sum of the masses of its nucleons.

<em>Calculate the mass defect </em>

  16 p = 16 × 1.007 28 u =  16.116 48  u

  16 n = 16 × 1.008 67 u =  16.138 72  u

Total mass of nucleons = 32.255 20 u

             - Mass of S-32 = <u>31.972 070 u </u>

                 Mass defect =  0.283 13   u

Convert the <em>unified atomic mass units to kilograms</em>.

Mass defect

= \text{0.283 13 u} \times \frac{ \text{1.66 06} \times 10^{-27} \text{ kg}}{\text{1 u}}

= 4.700 \times 10^{-28} \text{ kg}

Use Einstein’s equation to <em>convert the mass defect into energy</em>

E = mc^{2}

E = 4.7000 \times 10^{-28} \text{ kg} \times (2.998 \times 10^{8} \text{ m}\cdot\text{s}^{-1})^{2} = 4.224 \times 10^{-11} \text{ J}

4 0
3 years ago
What can be said about a reaction with H = 62.4 kJ/mol and S = 0.145 kJ/(mol·K)?
Zigmanuir [339]
Answer:

At 430.34 K the reaction will be at equilibrium, at  T > 430.34 the reaction will be spontaneous, and at T < 430.4K the reaction will not occur spontaneously.

Explanation:

1) Variables:

G = Gibbs energy
H = enthalpy
S = entropy

2) Formula (definition)

G = H + TS

=> ΔG = ΔH - TΔS

3) conditions

ΔG < 0 => spontaneous reaction
ΔG = 0 => equilibrium
ΔG > 0 non espontaneous reaction

4) Assuming the data given correspond to ΔH and ΔS

ΔG = ΔH - T ΔS = 62.4 kJ/mol + T 0.145 kJ / mol * K

=>  T = [ΔH - ΔG] / ΔS

ΔG = 0 =>  T = [ 62.4 kJ/mol - 0 ] / 0.145 kJ/mol*K = 430.34K

This is, at 430.34 K the reaction will be at equilibrium, at  T > 430.34 the reaction will be spontaneous, and at T < 430.4K the reaction will not occur spontaneously.

3 0
3 years ago
Read 2 more answers
Why is the Universal Law of Gravitation is a scientific Law and not a theory?
scoundrel [369]
This is a law because it describes the force but makes not attempt to explain how the force works. A theory is an explanation of a natural phenomenon. Einstein's General Theory of Relativity explains how gravity works by describing gravity as the effect of curvature of four dimensional spacetime.
5 0
2 years ago
The valences of metal x,y and z are 1,2 and 3 respectively. What are the formulae of their;a) hydroxides, b) sulphates, c) hydro
Rina8888 [55]

Answer:

See answer below

Explanation:

AS we know that the valence for those metals X, Y, and Z are 1, 2 and 3, we can determine the formula of each compound.

1. Hydroxides.

An hydroxide is formed when an oxyde of a metal reacts with water. When this happens, the general molecular formula is:

Meₐ(OH)ₙ

Where:

a: valence or charge of the hydroxide (Which is -1)

n: valence of the metal.

Following this, the formula for X, Y and Z would be:

XOH

Y(OH)₂

Z(OH)₃

2. Sulphates

Sulphates follow a similar rule of hydroxide in the general molecular formula, but instead of having a charge of -1, it has a charge of -2 so:

Mₐ(SO₄)ₙ

So, following the rule:

X₂SO₄

Y₂(SO₄)₂ ------> YSO₄

Z₂(SO₄)₃

3. Hydrogens

Following the same rule as the previous, hydrogens works with a charge of -1, so:

MₐHₙ

Then:

XH

YH₂

ZH₃

4. Carbonates.

This follows the same rule as sulphates, with the same charge so:

Mₐ(CO₃)ₙ

Then:

X₂CO₃

YCO₃

Z₂(CO₃)₃

5. Nitrates

Follow the same rule as the hydroxides, with the same charge of -1.

Mₐ(NO₃)ₙ

Then:

XNO₃

Y(NO₃)₂

Z(NO₃)₂

6. Phosphates

In the case of phosphates, these have a charge of -3 so:

Mₐ(PO₄)ₙ

Then:

X₃PO₄

Y₃(PO₄)₂

Z₃(PO₄)₃ ----> ZPO₄

Hope this helps

6 0
3 years ago
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