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Gemiola [76]
3 years ago
5

If the box weighs 40 newtons and is lifted a distance of 2 meters, how much work is done on the box?

Physics
1 answer:
Zarrin [17]3 years ago
5 0

Answer:

The work done on the box is 80 J.

Explanation:

Given that,

Weight of box = 40 N

Distance = 2 meter

We need to calculate the work done

Using formula of work done

W=F\times x

W=mg\times x

Where, x = distance

mg = weight

Put the value into the formula

W=40\times2

W= 80\ Nm

W=80\ J

Hence, The work done on the box is 80 J.

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Lostsunrise [7]

Answer:

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Explanation:

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3 years ago
A small object carrying a charge of -2.50 nc is acted upon by a downward force of 18.0 nn when placed at a certain point in an e
Vesna [10]
Missing question in the text:
"A.What are the magnitude and direction of the electric field at the point in question?

B.<span>What would be the magnitude and direction of the force acting on a proton placed at this same point in the electric field?"</span>

<span>Solution:

A) A charge q </span>under an electric field of intensity E will experience a force F  equal to:

F=qE

In our problem we have q=-2.5 nC=-2.5\cdot 10^{-9} C and F=18 nN = 18 \cdot 10^{-9} N, so we can find the magnitude of the electric field:

E= \frac{F}{q}= \frac{18\cdot 10^{-9}N}{2.5\cdot 10^{-9}C}=7.2 V/m

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B) The proton charge is equal to

e=1.6\cdot 10^{-19} C

Therefore, the magnitude of the force acting on the proton will be

F=eE=1.6\cdot 10^{-19} C \cdot 7.2 V/m=1.15 \cdot 10^{-18} N

And since the proton has positive charge, the verse of the force is the same as the verse of the field, so upward.

7 0
3 years ago
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IgorC [24]
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3 years ago
Consider the rocket in the image. Which unbalanced force accounts for the direction of the net force of the rocket ?
Wittaler [7]

Answer:

unbalenced force

Explanation:

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3 0
3 years ago
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Sue and Jenny kick a soccer ball at exactly the same time. Sue’s foot exerts a force of 75.9 N to the north. Jenny’s foot exerts
Lady_Fox [76]

Answer:

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