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Gemiola [76]
4 years ago
5

If the box weighs 40 newtons and is lifted a distance of 2 meters, how much work is done on the box?

Physics
1 answer:
Zarrin [17]4 years ago
5 0

Answer:

The work done on the box is 80 J.

Explanation:

Given that,

Weight of box = 40 N

Distance = 2 meter

We need to calculate the work done

Using formula of work done

W=F\times x

W=mg\times x

Where, x = distance

mg = weight

Put the value into the formula

W=40\times2

W= 80\ Nm

W=80\ J

Hence, The work done on the box is 80 J.

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The image is formed by a convex lens with the object at 2F.

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6 0
2 years ago
a current of 5 ampere is passed for 2 hours in an electric iron having a resistance of 100 ohms calculate the heat produced
Alina [70]

Answer:

\boxed{\sf Heat \ produced \ (H) = 5 \ kWh}

Given:

Resistance (R) = 100 Ω

Current (I) = 5 A

Time (t) = 2 hours

To Find:

Heat developed (H) in the electric iron

Explanation:

Formula:

\boxed{ \bold{ \sf H = I^2Rt}}

Substituting values of I, R & t in the equation:

\sf \implies H =  {5}^{2}  \times 100 \times 2 \\  \\ \sf \implies H = 25 \times 100 \times 2 \\  \\  \sf \implies H = 5000  \\  \\ \sf \implies H = 5 \: kWh

\therefore

Heat developed (H) in the electric iron = 15 kWh

3 0
4 years ago
What is an atom? Give three 3 examples.​
Assoli18 [71]

Answer:

<u>Atom</u><u> </u><u>is </u><u>particle</u><u> </u><u>of </u><u>matter</u><u> </u><u>that </u><u>uniquely</u><u> </u><u>defines</u><u> </u><u>a</u><u> </u><u>chemical</u><u> </u><u>element</u><u>.</u>

Examples of atom:

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  • Neon [Ne]
  • Argon [A]
  • Iron [Fe]
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<h3>About Atom:</h3>

Atom consists of a central nucleus that is usually surrounded by one or more electrons .Each electron is negatively charged. The nucleus is positively charged and contains one or more relatively heavy particles known as protons and neutrons.

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Hope this helps....

Good luck on your assignment...

8 0
3 years ago
describe in words the shape of the velocity vs. time graph. how is this related to the shape of the position vs. time graph
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Starting from a state of no rotation, a cylinder spins so that any point on its edge has a contant tangential acceleration of 3.
Leni [432]

Answer:

Explanation:

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= 3.1 / r , r is radius of the cylinder .

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