Answer:
There are 6.024 grams of sodium hydroxide in the solution.
Explanation:
Moles of sodium hydroxide = n
Volume of sodium hydroxide solution = 251.0 mL = 0.251 L
Molarity of the sodium hydroxide = 0.600 M
Mass of 0.1506 moles of NaOH :
There are 6.024 grams of sodium hydroxide in the solution.
Calculating K from Known Initial Amounts and the Known Change in Amount of One of the Species<span>Write the equilibrium expression for the reaction.Determine the molar concentrations or partial pressures of each species involved.<span>Determine all equilibrium concentrations or partial pressures using an ICE chart.</span></span>
Answer:
Substance A is a base and Substance B is an acid.
According to the experimental results
The amount of the solute is constant during dilution. So the mole number of HCl is 2*1.5=3 mole. The volume of HCl stock is 3/12=0.25 L. So using 0.25 L stock solution and dilute to 2.0 L.
(CH3)3N + H2O ---> (CH3)3NH+ + OH-
The equation of Kb:
Kb = [(CH3)3NH+][OH-]/[(CH3)3N]
<h3>
What do we know about the process of dissolution?</h3>
A solute can dissolve in a solvent in a solid, liquid, or gaseous phase to create a solution through the process of dissolution. Solubility. The greatest amount of a solute that may dissolve in a solvent at a particular temperature is known as its solubility. The solution is said to as saturated when the maximum amount of solute is present.
Several variables influence solubility, including:
- The solute's concentration
- The system's temperature
- Pressure (for gases in solution)
- The solvent's and solute's polarity
To learn more about pKb:
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