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makkiz [27]
2 years ago
9

Define the following:

Chemistry
1 answer:
Advocard [28]2 years ago
8 0

Answer:

A. Passive Transport is migration of a molecule from one side of the cell membrane to the other, from an area of high electrochemical potential to a region of lower electrochemical potential.

B. Diffusion is an individual molecule of a material moving from a high-concentration location to a low-concentration area over a semipermeable barrier

C. Osmosis is the movement of molecules of water through a cell's partly permeable membrane from a liquid with a large concentration of water molecules to a solution with a lower concentration of water molecules.

D. Facilitated Diffusion are molecules that diffuse across the plasma membrane with assistance from membrane proteins, such as channels and carriers.

E. Active transport is the transport of molecules across a cell membrane against a concentration gradient from a low-concentration region to a high-concentration region.

F. Selectively permeable is when some chemicals or ions pass across the membrane, while others are blocked.

G. Cellular respiration are organisms mix oxygen with food molecules, directing the chemical energy in these substances into life-sustaining processes while eliminating carbon dioxide and water as waste material.

Explanation:

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If 16.29 grams of Na2SO4 is mixed with 3.697 grams of C and allowed to react according to the balanced equation: Na2SO4(aq) + 4
abruzzese [7]

<u>Answer:</u> The limiting reagent in the given chemical reaction is carbon metal.

<u>Explanation:</u>

Excess reagent is defined as the reagent which is present in large amount in a chemical reaction.

Limiting reagent is defined as the reagent which is present in small amount in a chemical reaction. Formation of product depends on the limiting reagent.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For sodium sulfate:</u>

Given mass of sodium sulfate = 16.29 g

Molar mass of sodium sulfate = 142 g/mol

Putting values in equation 1, we get:

\text{Moles of sodium sulfate}=\frac{16.29g}{142g/mol}=0.115mol

  • <u>For carbon:</u>

Given mass of carbon = 3.697 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon}=\frac{3.697g}{12g/mol}=0.31mol

For the given chemical reaction:

Na_2SO_4(aq.)+4C(s)\rightarrow Na_2S(s)+4CO(g)

By Stoichiometry of the reaction:

4 moles of carbon reacts with 1 mole of sodium sulfate

So, 0.31 moles of carbon will react with = \frac{1}{4}\times 0.31=0.0775mol of sodium sulfate

As, given amount of sodium sulfate is more than the required amount. So, it is considered as an excess reagent.

Thus, carbon metal is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent in the given chemical reaction is carbon metal.

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Ionic compound is formed by negative and positive ions, these ions form ionic bond
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Answer: It changed in identity and properties.

Explanation:

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Answer: The solution will remain yellow.

Explanation:

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