Answer:
So trees in temperate don't lose their leaves because the weather events aren't harsh enough.
Trees in tropical rainforest don't lose their leaves because they are a different type of tree known as evergreens that are green all year round.
Explanation:
Ok so first we'll define some things
Deciduous Trees= Trees that lose all of their leaves for part of the year.
Trees shed their leaves trees to try and survive harsh weather events.
Temperate deciduous trees lose their leaves in fall to better survive the winter conditions of extreme cold and reduced daylight.
Temperate rainforests = An area that doesn't experience extremely cold or extremely hot temperatures or what we would call harsh weather events.
Broad-leaved trees in tropical rainforests are known evergreen, they are known as this as they are green all year round.
Oxidation state of I is (-1) and for CO it is zero. Let's assume that the oxidation state of Fe in Fe(CO)₄I₂<span> (s) is x. For whole compound, the charge is zero.
Sum of oxidation numbers in all elements = Charge of the compound.
Here we have 1Fe , 4CO and 2I
hence we can find the oxidation state as;
x + 4*0 + 2*(-1) = 0
x + 0 - 2 = 0
x = +2
Hence the oxidation state of Fe in product </span>Fe(CO)₄I₂ (s) is +2.
Same as we can find the oxidation state (y) of Fe in Fe(CO)₅(s).
y + 5*0 = 0
y = 0
Since oxidation state of Fe increased from 0 to +2, the oxidized element is Fe in the given reaction.
Carbon monoxide (CO) is the name
The correct answers would be A, and D