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pochemuha
2 years ago
9

1

Chemistry
1 answer:
Effectus [21]2 years ago
4 0

Answer:

There are 5! goodluck,

Explanation:

You might be interested in
Part iii. Is the dissolution reaction of ammonium nitrate enthalpy favored?
lesya [120]

Answer:

No, it is not enthalpy favored since the chemical system gains energy.

Explanation:

The dissolution of ammonium nitrate in water is an endothermic process.

Endothermic process requires the system to gain energy to can dissolve the particles in water.

So, the reaction is not enthalpy favored.

3 0
3 years ago
How many atoms of carbon are in the sample
Serhud [2]
There are six atoms in the carbon
6 0
3 years ago
A sample of an ideal gas at 1.00 atm and a volume of 1.87 L was placed in a weighted balloon and dropped into the ocean. As the
Ludmilka [50]

Answer:

Volume of sample after droping into the ocean=0.0234L

Explanation:

As given in the question that gas is idealso we can use ideal gas equation to solve this;

Assuming that temperature is constant;

Lets P_1 and V_1 are the initial gas parameter before dropping into the ocean

and P_2 and V_2 are the final gas parameter after dropping into the ocean

according to boyle 's law pressure is inversly proportional to the volume at constant temperature.

hence,

P_1V_1=P_2V_2

P1=1 atm

V1=1.87L

P2=80atm

V2=?

After putting all values we get;

V2=0.0234L

Volume of sample after droping into the ocean=0.0234L

7 0
3 years ago
Helppppp with this pleasee
vazorg [7]

Answer:

A. 1, 2, 5

Explanation:

Count the number of Ns in the formula.

- Hope that helped! Please let me know if you need a further explanation.

3 0
3 years ago
the temperature of a sample of water increases from 20celsius to 46.6celsius as it absorbs 5650 J of heat. what is the mass of t
Levart [38]

Answer:

m = 50.74 kg

Explanation:

We have,

Initial temperature of water is 20 degrees Celsius

Final temperature of water is 46.6 degrees Celsius

Heat absorbed is 5650 J

It is required to find the mass of the sample. The heat absorbed is given by the formula ad follows :

Q=mc\Delta T

c is specific heat of water, c = 4.186 J/g°C

So,

m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{5650}{4.186\times (46.6-20)}\\\\m=50.74\ kg

So, the mass of the sample is 50.74 kg.

8 0
3 years ago
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