1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
77julia77 [94]
2 years ago
11

Does a precipitate form when you react zinc with potassium phosphate?

Chemistry
1 answer:
Nastasia [14]2 years ago
3 0

Answer:

yes

Explanation:

You might be interested in
Select the correct answer. What is heat of vaporization? A. It is the heat required to change a substance’s temperature by 1°C.
Luba_88 [7]

D. It is the heat required to change a gram of substance from a liquid to a gas.

Explanation:

The heat of vaporization is the heat required to change a gram of substance from a liquid to a gas.

  • It is also known as the enthalpy of vaporization.
  • The heat of vaporization is the quantity of heat needed to change one gram of a substance from liquid to gas.
  • This heat of vaporization is dependent on the pressure conditions the process is taking place.
  • Different liquids have their heat of vaporization.

learn more:

Heat of vaporization brainly.com/question/9529654

#learnwithBrainly

7 0
3 years ago
The nonvolatile, nonelectrolyte estrogen (estradiol), C18H24O2 (272.40 g/mol), is soluble in chloroform CHCl3.
Artist 52 [7]

<u>Answer:</u> The molarity of solution is 0.274 M and the osmotic pressure of the solution is 6.70 atm

<u>Explanation:</u>

To calculate the molarity of the solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Given mass of estrogen = 13.5 g

Molar mass of estrogen = 272.40 g/mol

Volume of solution = 181 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{13.5\times 1000}{272.40\times 181}\\\\\text{Molarity of solution}=0.274M

Hence, the molarity of solution is 0.274 M

To calculate the osmotic pressure of the solution, we use the equation:

\pi=iMRT

where,

\pi = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = 0.274 M

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature of the solution = 298 K

Putting values in above equation, we get:

\pi=1\times 0.274mol/L\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\\pi=6.70atm

Hence, the osmotic pressure of the solution is 6.70 atm

8 0
3 years ago
Imagine that you are given the mass spectra of these two compounds, but the spectra are missing the compound names.
12345 [234]

The structures of the isomers and the m/z values of their peaks are not given in the question. The complete question is provided in the attachment

Answer:

Compound 2 (2,5-dimethylhexane) will not have the peaks at 29 and 85 m/z

Explanation:

The fragmentation of molecules by electron ionization of mass spectrometer occurs according to Stevenson's Rule, which states that "The most probable fragmentation is the one that leaves the positive charge on the fragment with the lowest ionization energy". This is much like the Markovnikov's Rule in organic chemistry which has predicted the formation of most stable carbocation and the addition of hydrogen halide to it.

The mass spectra of compound 1 (2,4-dimethylhexane) will contain all the m/z values mentioned in the question. Each peak indicate towards homologous series of fragmentation product of the compound 1. The first peak can be attributed to ethyl carbocation (m/z = 29), with the increase of 14 units the next peak indicates towards propyl carbocation (m/z = 43) and onwards until molecular ion peak of 114 m/z.

Compound 2 (2,5-dimethylhexane) structure shows that the cleavage  of C-C bond will not yield a stable ethyl and hexyl carbocation. Hence, no peaks will be observed at 29 and 85 m/z. The absence of these two peaks can be used to distinguish one isomer from the other.

5 0
3 years ago
Identify the reactant that gets oxidized in the following reaction.
Nat2105 [25]

Answer:

E) This is not an Oxidation/ Reduction type of reaction

Explanation:

Oxidation involves the loss of electrons while reduction involves the addition of electrons. None of the elements change their oxidation number in the reaction, so this is not an oxidation/reduction type of reaction.

6 0
2 years ago
The equation for density, d, is
Zanzabum
Mass (g) / Volume (cm^3) = Density (g/cm^3)

60.4g/ 11.3 cm^3 = 5.35 g/cm^3

d= 5.35 g/cm^3
7 0
2 years ago
Other questions:
  • Could use some help on this one
    9·1 answer
  • Matter is anything that has
    11·1 answer
  • Calculate the mass (in grams) of silver in 10.0 grams of silver sulfide ag2s
    11·1 answer
  • What substances can be separated into simpler substances only by chemical means?
    12·1 answer
  • Suppose that the root-mean-square velocity vrms of water molecules (molecular mass is equal to 18.0 g/mol) in a flame is found t
    6·1 answer
  • The oil window is the Choose one:_______
    10·1 answer
  • Which ionic compounds are not likely to dissolve in water?(More than 1 answer.)
    5·1 answer
  • Record the volume of the liquid in the graduated cylinder. The volume of the liquid is
    12·1 answer
  • A gate made of painted iron is beginning to rest in areas where the paint has worn away why is the formation of rust considered
    6·1 answer
  • Draw the structure of 2 methyl,but-3-ene
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!