The balanced equation for the above reaction is as follows;
Mg + 2HCl ---> MgCl₂ + H₂
stoichiometry of HCl to MgCl₂ is 2:1
we have been told that Mg is in excess therefore HCl is the limiting reactant
number of HCl moles reacted - 0.100 mol/L x 0.0256 L = 0.00256 mol
according to molar ratio, number of MgCl₂ moles formed - 0.00256/2
Therefore number of MgCl₂ moles formed - 0.00128 mol
mass of MgCl formed - 0.00128 mol x 95.20 g/mol = 0.122 g
The relation between density and mass and volume is
the dose required is 2.5 tsp
each tsp contain 5mL
So dose required in mL = 2.5 X 5 = 12.5 mL
the mass will be calculated using following formula
The mass of dose in grams will be 15.38 g
Answer: 207.217 amu
Work:
203.973 amu *(0.014) = 2.855 amu
205.974 amu *(0.241) = 49.639 amu
206.976 amu *(0.221) = 45.741 amu
207.977 amu *(0.524) = 108.979 amu
2.855 + 49.639 + 45.741 + 108.979 = <em><u>207.217amu</u></em>
Explanation:
To find molarity
We need no.of moles and solution in liter
Given data is in grams and ml
We have to convert it in required units
For no.of moles use formula
No.of mole=mass in gram / molar mass
Mass in gram = 29.1g
Molar mass = 160.4374g/mol calculated by adding the atomic wight of all atoms in LiClO4.3H2O
Atomic weight
Li= 6.941
Cl= 35.453
O= 15.9994
H= 1.00794
Now put it in mol equation
No.of mole = 29.1/160.4374
= 0.181mol of solute
Now convert solution in L from ml
235ml = 235/1000 = 0.235L
Now put these values in molarity formula
Molarity= 0.181/0.235
= 0.77M solution
Answer:
C) Mercury based thermometer
Explanation:
