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2 years ago

Which of the following correctly represents an ion pair and the ionic compound the ions form

Chemistry

2 answers:

krok68 [10]2 years ago

6 0

Answer:

It's a.

Explanation:

That would be Ca2+ , F- . We see in the compound CaF2 the signs balance to give a neutral compound, 2+ balances with 2-.

lesya692 [45]2 years ago

5 0

Answer: a. $Ca^{2+}$ , $F^-$ , $CaF_2$

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

(a) calcium and ﬂuorine: Here calcium is having an oxidation state of +2 called as $Ca^{2+}$ cation and fluorine $F^{-}$ is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $CaF_2$ . called as calcium fluoride.

(b) sodium and chlorine: Here sodium is having an oxidation state of +1 called as $Na^{+}$ cation and chlorine $Cl^{-}$ is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $NaCl$ called as sodium chloride.

(c) barium and oxygen : Here barium is having an oxidation state of +2 called as $Ba^{2+}$ cation and oxygen $O^{2-}$ is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $BaO$ called as barium oxide.

(d) lead and oxygen : Here lead is having an oxidation state of +4 called as $Pb^{4+}$ cation and oxygen $O^{2-}$ is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $PbO_2$ called as lead(IV) oxide.

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Which of these is not an example of a molecule?

r-ruslan [8.4K]

Answer:

Explanation:

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3 years ago

What is the section of lithosphere that carries crust

Tanya [424]

The best answer that I can give you is, the Plate.

6 0

3 years ago

Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I

Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, $1.077\times 10^9$

Explanation :

First we have to calculate the moles of iron.

$\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles$

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains $6.022\times 10^{23}$ number of iron atoms

So, 0.0519 mole of iron contains $0.0519\times 6.022\times 10^{23}=3.125\times 10^{22}$ number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = $\frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}$

Number of iron atoms are present in each red blood cell = $\frac{3.125\times 10^{22}}{2.90\times 10^{13}}$

Number of iron atoms are present in each red blood cell = $1.077\times 10^9$

Therefore, the number of iron atoms present in each red blood cell are, $1.077\times 10^9$

6 0

2 years ago

1. 90.0 mL of distilled water is added to a 10.0mL sample of 0.150mol/L sodium

aniked [119]

Answer: dilute

Explanation:

A concentrated solution which is used to prepare solutions of lower concentrations by diluting it with addition of water.

A dilute solution is one which contains lower concentration.

Using Molarity equation:

$M_1$ =concentration of stock solution = 0.150 mol/L

$V_1$ = volume of stock solution = 10.0 ml

$M_2$ = concentration of dilute solution = ?

$V_2$ = volume of dilute solution = (10.0+90.0) ml = 100.0 ml

$0.150\times 10.0=M_2\times 100.0$

$M_2=0.015mol/L$

As the concentration is less than the original concentration, the solution is termed as dilute.

7 0

2 years ago

PLEASE HELP DUE SOON

jonny [76]

Answer:

This is all true if the atom has to be neutral.

Also what does V mean?

Helium: one shell with 2 neutrons and 2 protons in the center, with 2 electrons in the first shell.

Lithium: two shells with 4 neutrons and 3 protons in the center, with 2 electrons in the first shell, and 1 electron in the second shell.

Nitrogen: two shells with 7 neutrons and 7 protons in the center, with 2 electrons in the first shell, and 5 electrons in the second shell.

Flourine: two shells with 9 protons and 10 neutrons in the center, with 2 electrons in the first shell, and 7 electrons in the second shell.

Neon: two shells with 10 neutrons and 10 protons in the center, with 2 electrons in the first shell, and 8 electrons in the second shell.

Boron: two shells with 6 neutrons and 5 protons in the center, with 2 electrons in the first shell, and 3 electrons in the second shell.

3 0

2 years ago