as it is given that
now we will have
now the magnitude of this vector is given as
now to find the direction we can use
Two identical small metal spheres with q1 > 0 and |q1| > |q2| attract each other with a force of magnitude 81 mN when sepa
rated by a distance of 2.86 m .The spheres are then brought together until they are touching, enabling the spheres to attain the same final charge q. After the charges on the spheres have come to equilibrium, they spheres are separated so that they are again 2.65 m apart. Now the spheres repel each other with a force of magnitude 12.15 mN.
a. What is the final charge on the sphere on the right?
b. What is the initial charge q1 on the first sphere?
a. What is the final charge on the sphere on the right?
b. What is the initial charge q1 on the first sphere?
1 answer:
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The resultant speed of the plane is (3) 226 m/s
Why?
We can calculate the resultant speed of the plane by using the Pythagorean Theorem since both speeds are perpendicular (forming a right triangle).
So, calculating we have:
Hence, we have that the resultant speed of the plane is (3) 226 m/s
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Answer
given,
Mass of the runner, M = 70 Kg
speed of the runner on the second base = 4.35 m/s
speed at the base = 0 m/s
Acceleration due to gravity,g = 9.8 m/s²
a) magnitude of mechanical energy lost
Mechanical energy lost is equal top gain in kinetic energy
b) Work done = Force x displacement
W = F. x
F = μ mg
W = μ mg . x
Work done is equal to 662.29 J
using the coefficient of the friction,μ = 0.7
x = 1.38 m
Hence, the runner will slide to 1.38 m.