Two identical small metal spheres with q1 > 0 and |q1| > |q2| attract each other with a force of magnitude 81 mN when sepa
rated by a distance of 2.86 m .The spheres are then brought together until they are touching, enabling the spheres to attain the same final charge q. After the charges on the spheres have come to equilibrium, they spheres are separated so that they are again 2.65 m apart. Now the spheres repel each other with a force of magnitude 12.15 mN.
a. What is the final charge on the sphere on the right?
b. What is the initial charge q1 on the first sphere?
a. What is the final charge on the sphere on the right?
b. What is the initial charge q1 on the first sphere?
1 answer:
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Answer:
28,400 N
Explanation:
Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:
On the lower part of the hatch, there is a pressure equal to
So, the net pressure acting on the hatch is
which acts from above.
The area of the hatch is given by:
So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch: