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mrs_skeptik [129]
3 years ago
12

16. At a particular point, a satellite in an elliptical orbit has a gravitational potential energy of 7000 MJ with respect to Ea

rth’s surface and a kinetic energy of 4000 MJ. At another point in its orbit, the satellite’s potential energy is 2000 MJ. What is its kinetic energy at that point? Show all calculations leading to your answer.
Physics
1 answer:
WARRIOR [948]3 years ago
8 0
Assuming conservation of energy:

Energy before = 7000 + 4000 = 11 000 MJ

Energy after = 2000 + Kinetic = 11 000

Therefore Kinetic = 11 000 - 2 000

Kinetic = 9 000 MJ
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Difference between inverted and upright microscope
ser-zykov [4K]
An Inverted Microscope gives you more freedom than an upright microscope. Inverted microscopes are very useful to examine the surface of heavy and large sized Items for industrial purposes. Whereas <span>upright microscopes have very limited distance between the table and the objective.</span>
6 0
3 years ago
As a space shuttle moves through the dilute ionized gas of Earth's ionosphere, the shuttle's potential is typically changed by -
postnew [5]

Answer:

-2.3 × 10^-9 Coulombs(C).

Explanation:

So, we are given the following data or information or parameters that is going to help us to solve the problem effectively and efficiently;

=> " the shuttle's potential is typically changed by -1.4 V during one revolution. "

=> " Assuming the shuttle is a conducting sphere of radius 15 m".

So, in order to estimate the value for the charge we will be making use of the equation below:

Charge, C =( radius × voltage or potential difference) ÷ Coulomb's law constant.

Note that the value of Coulomb's law constant = 9 x 10^9 Nm^2 / C^2.

So, charge = { 15 × (- 1.4)} / 9 x 10^9 Nm^2 / C^2.

= -2.3 × 10^-9 Coulombs(C).

4 0
3 years ago
What is the average speed of a kangaroo that hops 60 m in 5 s ?
jok3333 [9.3K]
The formula for average speed is
v_{avg}= \frac{total distance}{total time}
So we can just substitute our data.
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6 0
2 years ago
Read 2 more answers
Consider the equation . The dimensions of the variables v, x, and t are , , and , respectively. The numerical factor 3 is dimens
Vinvika [58]

Answer:

Part of the question is missing but here is the equation for the function;

Consider the equation v = (1/3)zxt2. The dimensions of the variables v, x, and t are [L/T], [L], and [T] respectively.

Answer = The dimension for z = 1/T3 i.e 1/ T - raised to power 3

Explanation:

What is applied is the principle of dimensional homogenuity

From the equation V = (1/3)zxt2.

  • V has  a dimension of [L/T]
  • x has a dimension of [L]
  • t has a dimension of [T]
  • from the equation, make z the subject of the relation
  • z = v/xt2 where 1/3 is treated as a constant
  • Substituting into the equation for z
  • z = L/T / L x T2
  • the dimension for z = 1/T3 i.e 1/ T - raised to power 3
5 0
3 years ago
Represent 0.783 kg with Sl units having an appropriate prefix Express your answer to three significant figures and include the a
zysi [14]

Answer:

783 grams

Explanation:

Here mass is given in kg

Some of the prefixes of the SI units are

1 gram = 10⁻³ kilogram

1 milligram = 10⁻⁶ kilogram

1 microgram = 10⁻⁹ kilogram

1 nanogram = 10⁻¹² kilogram

The number is 0.783

Here, the only solution where the number of significant figures is three is gram. If any other prefix is chosen then the significant figures will increase

1\ kilogram = 1000\ gram

\\\Rightarrow 0.783\ kilogram=0.783\times 1000\ gram\\ =783\ gram

So, 0.783 kg = 783 grams

5 0
3 years ago
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