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mrs_skeptik [129]
3 years ago
12

16. At a particular point, a satellite in an elliptical orbit has a gravitational potential energy of 7000 MJ with respect to Ea

rth’s surface and a kinetic energy of 4000 MJ. At another point in its orbit, the satellite’s potential energy is 2000 MJ. What is its kinetic energy at that point? Show all calculations leading to your answer.
Physics
1 answer:
WARRIOR [948]3 years ago
8 0
Assuming conservation of energy:

Energy before = 7000 + 4000 = 11 000 MJ

Energy after = 2000 + Kinetic = 11 000

Therefore Kinetic = 11 000 - 2 000

Kinetic = 9 000 MJ
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Initial velocity of the proton u = 0

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Since the proton is accelerating through a potential difference, proton's potential energy will change with time. The potential energy of a particle of charge q when accelerated with a potential difference \Delta V is,

    U = q \Delta V

Due to Work-Energy Theorem and Conservation of Energy - <em>If there is no non-conservative force acting on a particle then loss in Potential energy  P.E must be equal to gain in Kinetic Energy K.E</em> i.e

\Delta K = \Delta V

If the initial and final velocity of the proton is u and v respectively then,

change in Kinetic Energy  \implies  \Delta K = \frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}mv^2 - 0

change in Potential Energy \implies \Delta U = q\Delta V

from conservation of energy,

             v= \sqrt{\frac{2q\Delta V}{m}}

so,         v = \sqrt{\frac{2\times 350 \times 1.6\times 10^{-19}}{1.67 \times 10^{-27}}

                = 25.86 \times 10^4 ~m/s

To read more about the conservation of energy, please go to brainly.com/question/14668053

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