A 13-kg sled is moving at a speed of 3.0 m/s. At which of the following speed will the sled have twice as much kinetic energy?
<span>4.2 m/s</span>
Angular acceleration = (change in angular speed) / (time for the change)
Change in angular speed = (ending speed) minus (starting speed)
Change in angular speed = (16 rad/s) - (zero) = 16 rad/s .
Angular acceleration = (16 rad/s) / (0.4 s)
(Average) angular acceleration = 40 rad/s²
Answer:
s=1721.344m ,v=104.96m/s.
Explanation:
using thr equation of motion;

u=0, plane starts from rest,


s=1721.344m
v=u+at
v=0 +3.2*32.8
v=104.96m/s
Answer:
letter C. velocity hope this helps