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ICE Princess25 [194]
2 years ago
5

How do you find the slope of a force-extension graph?

Physics
1 answer:
Harrizon [31]2 years ago
3 0

The relationship between force and extension is a linear one, which means that if you plot a force vs. extension graph, you'll get a straight line. It will pass through the origin (x = 0; F = 0), and its slope will be equal to the spring constant, k.

Measure the Slope of the Force Extension Graph

In general, you can find the slope of a line by choosing two points and forming a ratio of the rise and the run between these two points. If the first point you choose is (x1, F1), and the second point is (x2, F2), the slope of the line is:

slope= f(2)- f(1)

           ---------

            x(2)-x(1)

Assuming F2 is larger than F1.

This is the value of the spring constant, k. Despite the minus sign in the Hooke's law equation, k is a positive number, because the slope in the Hooke's law graph is positive.

Note that the spring constant has units of force/distance. In the MKS system, the spring constant units are newtons/meter. In the CGS system, they are dynes/centimeter. In the imperial system, they are pounds of force (lbf) /foot.

Now that you have the spring constant, you can predict exactly how much the spring will distend or compress when you subject it to any force.

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Answer:

Explanation:

Given

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maximum acceleration=-6 m/s^2

distance=39 m

Let x be the distance traveled by motorist in his reaction time

therefore remaining 39-x will be traveled with -6m/s^2 acceleration

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s=39-x

v=0

u=12 m/s

0-12^2=2\left ( -6\right )\left ( 39-x\right )

x=27 m

Therefore he traveled 27 m in his reaction time

27=12\times t

t=2.25 s

(b)If his reaction time is 2.56 sec

then distance traveled in his reaction time

x_0=12\times 2.56=30.72 m

Remaining distance 39-30.72=8.28 m

therefore its velocity when it reaches the deer

v^2-u^2=2as

v^2=12^2+2\times \left ( -6\right )\times 8.28=44.64

v=6.681 m/s

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During a 0.001 s interval while it is between the plates, the change of the momentum of the electron Δp with arrow is &lt; 0, -8
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