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Virty [35]
2 years ago
5

¿Qué papel creen que cumplían en sus respectivas sociedades ? es para hoy porfis ayudemeee​

Chemistry
2 answers:
astraxan [27]2 years ago
8 0

Answer:

En términos generales, todos debemos desempeñar un papel particular en nuestra sociedad respectiva. Todo el mundo debe ser capaz de ser un buen ciudadano capaz de vivir y vivir juntos de acuerdo con las normas establecidas por la sociedad, guiados por las buenas convicciones que tenemos como seres humanos.

Sin embargo, creo que clasificando la sociedad por edad: niños, jóvenes, adultos y personas mayores.

Cada grupo desempeña un papel fundamental e idealista dentro de sus respectivas sociedades, los niños y las abuelas prácticamente comparten el papel de inspirarnos a construir un mejor presente y futuro, mientras que los jóvenes y los adultos construyen y materializan los sueños, para que cada generación pueda tener los mismos o más que los anteriores.

Explanation:

Espero que ayude!~ :)

pochemuha2 years ago
3 0

Answer:

I don't know spanish, ask someone else

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Which of the following is an example of oxidation? A. Charcoal is placed on a grill and lighting fluid poured over it. B. A car
Vikentia [17]

Answer:

<u>The Answer is (B)  A car get rusty over the course of few years</u>Explanation:

<u>Explanation:</u>

  • <u>Oxidation </u>refers to the process of loss of electrons by a molecule,atom or ion during a chemical reaction.The process which is just the opposite of oxidation is reduction,it occurs when their is gain of electrons .
  • <u>When iron reacts with the oxygen it forms a chemical know as Rust.In this case iron has lost some electrons and the oxygen has gained some electrons</u>

<u></u>

4 0
3 years ago
A cup has a mixture of iron filings, sand, and salt. How could you separate theses 3 materials? Write out the procedures you wou
Anarel [89]

Explanation:

A cup of mixtures of iron fillings, sand and salt is a mixture who constituents are in the same phase i.e solid.

To separate them out we use the physical properties of the substances.

  • First spread out the mixture uniformly over a piece of paper or on the table.
  • Pass a bar magnet over it.
  • The iron fillings will become attracted to the magnet and separate from the mixture.
  • then pour water into the mixture of sand and salt
  • the salt will dissolve since sand is made up of quartz which are highly insoluble.
  • separate the water solution. Evaporate to dryness and recover the salt.
  • the sand is left behind and dried.

learn more:

Mixtures brainly.com/question/1832352

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3 0
3 years ago
ou will prepare 250-mL of this solution using a 30% (m/v) NaOH stock solution. How many mL of the NaOH stock solution will you n
ArbitrLikvidat [17]

Answer:

\boxed{\text{3.3 mL}}

Explanation:

You must convert 30 % (m/v) to a molar concentration.

Assume 1 L of solution.

1. Mass of NaOH

\text{Mass of NaOH} = \text{1000 mL solution } \times \dfrac{\text{30 g NaOH}}{\text{100 mL solution}} = \text{300 g NaOH}

2. Moles of NaOH  

\text{Moles of NaOH} = \text{300 g NaOH} \times \dfrac{\text{1 mol NaOH}}{\text{40.00 g NaOH}} = \text{7.50 mol NaOH}

3. Molar concentration of NaOH

c= \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{7.50 mol}}{\text{1 L}} = \text{7.50 mol/L}

4. Volume of NaOH

Now that you know the concentration, you can use the dilution formula .

c_{1}V_{1} = c_{2}V_{2}

to calculate the volume of stock solution.

Data:

c₁ = 7.50 mol·L⁻¹; V₁ = ?

c₂ = 0.1   mol·L⁻¹; V₂ = 250 mL

Calculations:

(a) Convert millilitres to litres

V = \text{250 mL} \times \dfrac{ \text{1 L}}{\text{1000 mL}} = \text{0.250 L}

(b) Calculate the volume  of dilute solution

\begin{array}{rcl}7.50V_{1} & = & 0.1 \times 0.250\\7.50V_{1} &= & 0.0250\\V_{1} & = & \text{0.0033 L}\\& = & \textbf{3.3 mL}\\\end{array}

\text{You will need $\boxed{\textbf{3.3 mL}}$ of the stock solution.}

4 0
3 years ago
The boiling point elevation of an aqueous sucrose solution is found to be 0.39°C.
SVEN [57.7K]

Answer:

130.4 grams of sucrose, would be needed to dissolve in 500 g of water.

Explanation:

Colligative property of boiling point elevation:

ΔT = Kb . m . i

In this case, i = 1 (sucrose is non electrolytic)

ΔT = Kb . m

0.39°C = 0.512°C/m . m

0.39°C /0.512 m/°C = m

0.762 m (molality means that this moles, are in 1kg of solvent)

If in 1kg of solvent, we have 0.712 moles of sucrose, in 500 g, which is the half, we should have, the hallf of moles, 0.381 moles

Molar mass sucrose = 342.30 g/m

Molar mass . moles = mass

342.30 g/m . 0.381 m = 130.4 g

6 0
3 years ago
If you dissolve 50.0 grams of potassium bromide?
Sergio039 [100]
<span>masss % of KBr = mass of KBr/total mass of solution X 100 = 50/100 X 100 = 50 %</span>
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3 years ago
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