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Alenkasestr [34]
3 years ago
6

Use the diagram below modeling a football kicked from a horizontal surface B

Physics
2 answers:
Bas_tet [7]3 years ago
7 0

Answer:

<h3>B is right try that that's hard tho lol:) </h3>
djyliett [7]3 years ago
5 0
B is the correct one
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Volcanic eruption affects water drainage but what may that result in​
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Explosive eruptions can severely disturb landscapes downwind or downstream of volcanoes by damaging vegetation and depositing large volumes of erodible fragmental material. As a result, fluxes of water and sediment in affected drainage basins can increase dramatically.
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Has a definite shape and definite volume. Question 4 options: liquid gas solid
ad-work [718]

Answer:

solid

Explanation:

solid

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Are most main sequence stars larger or smaller than the sun?
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3 years ago
Unpolarized light with intensity 300 W/m^2 passes first through a polarizing filter with its axis vertical, then through a secon
SOVA2 [1]

Answer:

The angle from vertical of the axis of the second polarizing filter is 50.57⁰.

Explanation:

Given;

intensity of the unpolarized light, I₀ = 300 W/m²

intensity of emergent polarized light, I = 121 W/m²

let the angle from vertical of the axis of the second polarizing filter = θ

Apply Malus's law, intensity of emergent polarized light is given as;

I = I₀Cos²θ

Cos^2 \theta = \frac{I}{I_o} \\\\Cos^2 \theta =\frac{121}{300} \\\\Cos^2 \theta =0.4033\\\\Cos \theta = \sqrt{0.4033} \\\\Cos \theta = 0.6351\\\\\theta  = Cos^{-1} (0.6351)\\\\\theta  = 50.57 ^0

Therefore, the angle from vertical of the axis of the second polarizing filter is 50.57⁰.

8 0
3 years ago
A 2010 kg space station orbits Earth at an altitude of 5.35×105 m. Find the magnitude of the force with which the space station
Shkiper50 [21]

Answer:

Force, F = 16814.95 N

Explanation:

It is given that,

Mass of space station, m = 2010 kg

Altitude, d=5.35\times 10^5\ m

Mass of earth, m=5.98\times 10^{24} kg

Mean radius of earth, r=6.37\times 10^6\ m

Magnitude of force is given by :

F=G\dfrac{Mm}{R^2}

R = r + d

R=6.37\times 10^6\ m+5.35\times 10^5\ m=6905000\ m

F=6.67\times 10^{-11}\times \dfrac{2010\ kg\times 5.98\times 10^{24} kg}{(6905000\ m)^2}

F = 16814.95 N

So, the force between the space station and the Earth is 16814.95 N. Hence, this is the required solution.

8 0
3 years ago
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