Complete question:
The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The magnitude of the electric field between the plates is 100 kV/m. The plates each have an area of 2 x 10⁻³ m², and the spacing between the plates is 6 x 10⁻³ m. There is no dielectric between the plates. What is the charge on the capacitor?
Answer:
The charge on the capacitor is 1.77nC
Explanation:
Given;
magnitude of electric field between the plates, E = 100 kV/m
Area of each plate, A = 2 x 10⁻³ m²
Distance between the plates, d = 6 x 10⁻³ m
Charge on the capacitor is calculated as;
Q = CV
V = Ed


Therefore, the charge on the capacitor is 1.77nC
D because weight is not a constant, however; Matyer is a constant
Answer:
M = 5.882 10²³ kg
Explanation:
Let's use Newton's second law to analyze the satellite orbit around Mars.
F = m a
force is universal attraction and acceleration is centripetal
a = v²/ R
the modulus of velocity in a circular orbit is constant
v= d/T
the distance of the cicule is
d =2pi R
a = 2pi R/T
we substitute
- G m M / R² = m (
)
G M =
M = 
the distance R is the distance from the center of the planet Mars to the center of the satellite Deimos
R = 23460 km = 2.3460 10⁷ m
the period of the orbit is
T = 1,263 days = 1,263 day (24 h / 1 day) (3600s / h)
T = 1.0912 10⁵ s
let's calculate
M =
M = 509.73418 10²¹ /8.66640 10⁻¹
M = 58.817 10²² kg
M = 5.882 10²³ kg