Answer:
Ni
Explanation:
An active metal is a highly reactive metal. Active metals are found high up in the activity series.
Active metals react with other metals that are lower than them in the activity thereby displacing the lower metals from a solution of their salts. This is what may have happened in the other two reactions.
Ni is the most active metal listed in the question since it can react a compounds with Pb(NO3)2(aq) to liberate Pb metal.
The kinetic energy of the products is equal to the energy liberated which is 92.2 keV. But let's convert the unit keV to Joules. keV is kiloelectro volt. The conversion that we need is: 1.602×10⁻¹⁹ <span>joule = 1 eV
Kinetic energy = 92.2 keV*(1,000 eV/1 keV)*(</span>1.602×10⁻¹⁹ joule/1 eV) = 5.76×10²³ Joules
From kinetic energy, we can calculate the velocity of each He atom:
KE = 1/2*mv²
5.76×10²³ Joules = 1/2*(4)(v²)
v = 5.367×10¹¹ m/s
Answer:
melting point will be higher than that of pure ethyl acetate
Explanation:
The maximum safe operating temperature for this reaction is equal to 895°C.
<u>Given the following data:</u>
- Width of cylinder = 22 cm.
- Maximum safe pressure = 6.30mpa.
<u>Scientific data:</u>
- Ideal gas constant, R = 8.314 L-kPa/Kmol.
- Molar mass of of dinitrogen monoxide () gas = 66 g/mol.
Radius, r =
<h3>How to calculate the maximum safe operating temperature.</h3>
First of all, we would determine the volume of the stainless-steel cylinder by using this formula:
Volume, V = 10,036.81 .
In liters, we have:
Volume, V = 10.04 Liters.
Next, we would determine the number of moles of dinitrogen monoxide () gas:
Number of moles = 8.136 moles.
Now, we can solve for the maximum safe operating temperature by applying the ideal gas equation:
T = 895.02 ≈ 895°C.
Read more on temperature here: brainly.com/question/24769208
Answer : The molar concentration of is,
Explanation : Given,
Equilibrium constant =
Concentration of = 0.050 M
The balanced equilibrium reaction is,
The expression of equilibrium constant for the reaction will be:
Now put all the values in this expression, we get :
Therefore, the molar concentration of is,