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kati45 [8]
3 years ago
5

PLEASE HELP I BEG

Chemistry
1 answer:
Gwar [14]3 years ago
5 0

Answer:

1.Velocity and pitch

2.The unit of vibration is hertz. The number of oscillations of an oscillating body per second is known as frequency. Complete step by step answer: The time taken by a vibrating body to complete one vibration is time period.

3.Frequencies above 20,000 Hz are known as ultrasound.

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How many particles are in one mole substance
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Avogadro's number is defined as the number of elementary particles (molecules, atoms, compounds, etc.) per mole of a substance. It is equal to 6.022×1023 mol-1 and is expressed as the symbol NA.

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This graph shows two curves pertaining to a hydrogen s orbital.
fgiga [73]

Answer 1) : According to the complete question attached in the answer,

The radial wave function  which is denoted by R_{nl}(r) shown with orange color crosses through zero point. Also, At the the radial nodes, which are spherical shells to some radial distance away from the nucleus there no electron are found.

Also, the radial probability distribution curve denoted as R^{2}_{nl}(r) shown in  blue  color is observed to touch zero, and shows the place of radial node.

Therefore, the total number of nodes will include both the kinds  which has radial and angular nodes which will be represented by <em>'n'</em>.

It is observed that for any atomic orbital, the total number of nodes will be n-1  .


Considering the s orbital of the hydrogen, which has zero angular momentum  (l); (l=0), as it has zero angular nodes.  

Hence, there will be only radial nodes, which is

(n−1  =  total number of radial nodes in s orbitals)

According to the image, there are 4  radial nodes shown, so n  =  5  (as n-1 = 4; therefore, n = 5)

This represents the 5s orbital.


Answer 2) The radial nodes are observed in I'm seeing radial nodes at  

1.9a_{0},  6.4a_{0},13.9a_{0} and  27.0a_{0}.

where  a_{0} represents the  hydorgen bohr atomic radius =  0.0529177 nm


Explanation : It is quite easy to observe the given graph and find out the approximate values of the radial nodes, it does not requires any equation to be solved. Equation can be used to find the radial nodes if it was supplied along with the question. Although by mere speculation one can find out the answer.

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