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earnstyle [38]
3 years ago
13

Alluvial fans form mostly in what regions

Chemistry
1 answer:
maxonik [38]3 years ago
6 0

Answer:

what is this

?????????

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Why would a crash involving cars going faster do more damage than a crash going slow? explain using terms kinetic and potential
erastovalidia [21]

At high speeds, there is more kinetic energy involved - more energy that will be converted to other forms of energy. This includes breaking a car, or body parts of people involved.

6 0
3 years ago
What would be the freezing point of a solution that has a molality of 1.468 m which was prepared by dissolving biphenyl (C12H10)
Readme [11.4K]

Answer:

Freezing point solution = 70.131 °C

Explanation:

Step 1: Data given

Molality = 1.468 molal

A solution is created by dissolving biphenyl (C12H10) into naphthalene

Biphenyl is a non-electrolyte

Freezing point of naphthalene = 80.26 °C

Step 2: Calculate the freezing point depression

ΔT = i*Kf*m

⇒with ΔT = the freezing point depression = TO BE DETERMINED

⇒with i = the van't Hoff factor of biphenyl = 1

⇒with Kf = the freezing point depression constant of naphthalene = 6.90 °C/m

⇒with m = the molality = 1.468 molal

ΔT = 1 * 6.90 °C/m * 1.468 °C

ΔT = 10.13 °C

Step 3: Calculate the freezing point of the solution

ΔT = 10.13 °C

Freezing point solution = freezing point naphthalene - 10.13 °C

Freezing point solution = 80.26 °C - 10.129 °C

Freezing point solution = 70.131 °C

5 0
4 years ago
How many total electrons can there be in the n=4 orbital?
Arturiano [62]

Answer:

the total electron that can be in the n=4 orbital is 32

Explanation:

it is because the formula is 2n^2,if n=4then it is 2(4)^2=32

7 0
4 years ago
As the temperature is increased, the rate of a chemical reaction usually
katrin2010 [14]
Increases as well. More heat means more energy is being supplied.
4 0
3 years ago
The weight of an object is the product of its mass, m, and the acceleration of gravity, g (where g=9.8 m/s2). If an object’s mas
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Its weight is = m×g= 10×9.8
= 98 kg.m/s^2
5 0
3 years ago
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