3 years ago

Alluvial fans form mostly in what regions

Chemistry

1 answer:

maxonik [38]3 years ago

6 0

Answer:

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3 years ago

What is the temperature difference if 300 cal are used to warm water

PIT_PIT [208]

Answer:

The temperature difference is $\frac{300}{m} Kkg^{-1}$

Explanation:

The formula that is to used is :

Δ $Q=ms$ Δ $T$

where ,

Δ $Q$ is the heat supplied in calories = 300cal
$m$ is the mass of water taken = m (assumed)
Δ $T$ is the change in temperature
$s$ is the specific heat of water = $1calK^{-1}Kg^{-1}$

ΔT :

$\frac{300}{m*1} \\=\frac{300}{m} Kkg^{-1}$

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The integrated rate law expression for a first order reaction is

$ln\frac{[A_{0}]}{[A_{t}]}=kt$

where

[A0]=100

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[6.25% of 100 = 6.25]

k = 9.60X10⁻³s⁻¹

Putting values

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taking log of 100/6.25

100/6.25 = 16

ln(16) = 2.7726

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