The solution would be like
this for this specific problem:
<span>
The force on m is:</span>
<span>
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] ->
1
The force on 2m is:</span>
<span>
GM(2m) / (L - x)^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2]
-> 2
From (1), you’ll get M = 2mx^2 / L^2 and from
(2) you get M = m(L - x)^2 / L^2
Since the Ms are the same, then
2mx^2 / L^2 = m(L - x)^2 / L^2
2x^2 = (L - x)^2
xsqrt2 = L - x
x(1 + sqrt2) = L
x = L / (sqrt2 + 1) From here, we rationalize.
x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1)
x = L(sqrt2 - 1) / (2 - 1)
x = L(sqrt2 - 1) </span>
= 0.414L
<span>Therefore, the third particle should be located the 0.414L x
axis so that the magnitude of the gravitational force on both particle 1 and
particle 2 doubles.</span>
6 is the answer I remember the answer from when I took this and it was easy
The displacement of the object as determined from the velocity-time graph is 562.5 m.
<h3>What is a velocity-time graph?</h3>
A velocity-time graph is a graph of the velocity of an object plotted in the vertical or y-axis of the graph against the time taken on the horizontal or x-axis.
The displacement of an object can be obtained from its velocity-time graph by calculating the total area under the graph.
The total area under the graph = area of triangle + area of rectangle
Area of triangle = b*h/2 =
Area of triangle = 25 * (35 - 10)/2 = 312.5 m
Area of rectangle = l * b
Area of rectangle = 10 * 25 = 250 m
Total area = (312.5 + 250) m
Total area = 562.5 m
Therefore, the displacement of the object is 562.5 m
In conclusion, the total area of a velocity-time graph gives the displacement.
Learn more about velocity-time graph at: brainly.com/question/28064297
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Answer:
sure, do you have more detailed of the assignments...?
Explanation:
