Answer:
See Explanation
Explanation:
The question is incomplete; as the mixtures are not given.
However, I'll give a general explanation on how to go about it and I'll also give an example.
The percentage of a component in a mixture is calculated as:

Where
E = Amount of element/component
T = Amount of all elements/components
Take for instance:
In 
The amount of all elements is: (i.e formula mass of
)



The amount of calcium is: (i.e formula mass of calcium)



So, the percentage component of calcium is:




The amount of hydrogen is:



So, the percentage component of hydrogen is:




Similarly, for oxygen:
The amount of oxygen is:



So, the percentage component of oxygen is:




Answer:
Metal is a conductor. it takes in heat very well. wood is an insulator. it takes in heat too, but less of it. this makes the wood handle cooler and the metal handle hot
We can solve the equation and show the solution below:
Oxygen atomic number is 16.
Phosphorus atomic number is 32.
We have the molecular weight:
Molecular weight = (31*4) + (16*10)
Molecular weight = 284 grams/mol
Solving for the grams:
0.4 mole (for P4) * (1 mol P4O10/1 mol P4) * (284 grams P4O10/1 mole P4O10)
Total grams = 113.6
The answer is 113.6 grams.
Answer:
a table of the chemical elements arranged in order of atomic number, usually in rows, so that elements with similar atomic structure (and hence similar chemical properties) appear in vertical columns.
Answer: Option (e) is the correct answer.
Explanation:
Equilibrium reaction equation for the given reaction is as follows.

It is given that initial moles of HCNO is 0.20 mol and for NaCNO is 0.80 mol.
of HCNO is
mol.
Now, we will assume that at equilibrium there are x moles.

Initial: 0.20 0.80 0
Change: -x +x +x
Equilibrium: 0.20 - x 0.80 + x x
As the volume of the given solution is 1 liter, equilibrium concentration and moles are same.
![K_{a} = \frac{[CNO^{-}][H_{3}O^{+}]}{[HCNO]}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BCNO%5E%7B-%7D%5D%5BH_%7B3%7DO%5E%7B%2B%7D%5D%7D%7B%5BHCNO%5D%7D)

x =
M
Then, pH = ![-log[H_{3}O^{+}]](https://tex.z-dn.net/?f=-log%5BH_%7B3%7DO%5E%7B%2B%7D%5D)
= 
= 4.30
Thus, we can conclude that pH of given buffer solution is 4.30.