Answer: 81%
Step-by-step explanation:
From the question, we are informed that a student received the following test scores: 71%, 89%, 72%,
84% and 83% in 5 tests and the student wants to maintain an average of 80%.
The lowest score/grade they can receive on the next test to maintain at least an 80% average first thus:
First, to make it easy we can remove the percent sign. Then we multiply 80 by 6 since we're calculating for 6 tests scores. This will be:
= 80 × 6
= 480
We then add all the 5 test scores. This will be:
= 71 + 89 + 72 + 84 + 83
= 399
We then subtract the values gotten. This will be:
= 480 - 399
= 81
This means the student must get at least 81%
It’s 2 and 3 bc 6a+12 and then 3(2a+4) and you need to distribute for that so 3 times 2a equals 6a and 3 times 4 equals 12 so you get 6a+12
Answer:
I'm not for sure about this one but if I did my math right it should be 68 sence it would be 48 if you didnt add 20
<span>The answer is true
Let's imagine that we have the following function function:
</span>
<span>We have to:
Independent variable: x
Dependent variable: y
For x = -1:
</span>
<span> For x = 1:
</span>
<span> We observe that the independent variable can only obtain one result.
Answer:
True</span>
Are you finding m? If so here is the answer:
75 = -5(3 + 6m)
Distribute:
75 = -15 - 30m
Add 15 to both sides:
75 = -15 - 30m
+15 +15
90 = -30m
Divide by -30 on both sides:
90/-30 = (-30m)/-30
You should get: m = -3
