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2 years ago

A quantity of gas occupies a volume of 804 mL at a temperature of 27 °C. At what temperature will the

Chemistry

1 answer:

irga5000 [103]2 years ago

3 0

Answer:

T₂ = 150 K

Explanation:

Given data:

Initial volume of gas = 804 mL

Initial temperature = 27°C (27+273=300 K)

Final temperature = ?

Final volume = 402 mL

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁/V₁

T₂ = 402 mL × 300 K / 804 mL

T₂ = 120,600 mL.K / 804 mL

T₂ = 150 K

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2 years ago

Fe(s) + 2HCl(aq) --> FeCl2(aq) + H2(g)

soldier1979 [14.2K]

Answer:

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Explanation:

$Fe(s) + 2HCl(aq)\rightarrow FeCl_2(aq) + H_2(g)
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