<h3>
Answer:</h3>
0.000538 mol Pb
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.24 × 10²⁰ particles Pb (lead)
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
Our final answer is in 3 sig figs, no need to round.
Answer:
The correct answer is 0.6 mL.
Explanation:
We use the mathematical expression:
Ci x Vi = Cf x Vf
Where Ci is the initial concentration (5 M); Cf and Vf refers to final concentration (0.002 M) and final volume (1500 mL). With the given data, we calculate the initial volume (Vi):
Vi = (Cf x Vf)/Ci = (0.002 M x 1500 mL)/(5 M) = 0.6 mL
Therefore, we need 0.6 mL of 5 M NaCl to prepare the solution with the requested dilution.
Answer:
11.32cm
Explanation:
This question describes a cylinder rod formed from silicon with length 21.3cm and mass 5kg. The density of the silicon is 2.33g/cm3.
To calculate the diameter, the radius is needed. To calculate the radius, the volume is needed. To calculate the volume, the formula: density = mass (m) / volume (V) is used.
Mass = 5kg, which is 5 kg × 1000g = 5000g
Density= 2.33g/cm3
Hence; volume= mass / density
= 5000/2.33
= 2145.9 cm3
Volume of cylinder= πr^2h
Where h= 21.3cm and π= 3.142
That is; r^2 = volume/πh
= r^2 = 2145.9/3.142×21.3
= r^2 = 2145.9/66.9246
= r^2 = 32.06
r= √32.06
r= 5.66cm
If radius of the cylinder is 5.66cm, the diameter is twice of the radius.
That is, diameter (d) = 5.66 × 2
= 11.32 cm
Therefore, the diameter of the cylinder is 11.32cm.
Answer:
i need a picture of ur question
Explanation:
Formula M1V1 =M2V2
1.5 * 100 = M2 *300
M2 = 1.5*100/300= 0.5.
Answer: the molarity is 0.5M.