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viktelen [127]
3 years ago
10

As an object fall in a gravitational field, its speed increases. This is an example of potential energy transforming into what?

Physics
1 answer:
IrinaK [193]3 years ago
5 0

Answer:

potential energy is transformed into kinetic energy

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A body is accelerated continuously. What is the form of the graph?
Inga [223]
That depends on what quantity is graphed.

It also depends on what kind of acceleration is taking place ...
continuous change of speed or continuous change of direction.

-- If the graph shows speed vs time, and the acceleration is a change
in speed, then the graph is a connected series of straight-line pieces. 
Each straight piece slopes up if speed is increasing, or down if speed
is decreasing.

-- If the graph shows speed vs time, and the acceleration is a change in
direction only, then the graph is a straight horizontal line, since speed is
constant.

-- If the graph shows direction vs time, and the acceleration is a change
in speed only, then the graph is a straight horizontal line, since direction
is constant.

-- If the graph shows direction vs time, and the acceleration is a change
in direction, then the graph is a connected series of pieces of line. 
Each piece may be straight if the direction is changing at a constant rate,
or curved if the direction is changing at a rate which grows or shrinks. 
Each piece may slope up if the angle that defines the direction is growing,
or may slope down if the angle that defines the direction is decreasing.

-- If the graph shows distance vs time, and the acceleration is a
change in speed, then the graph is a connected series of pieces
of curves.  Each piece curves up if speed is increasing, or down if
speed is decreasing.

-- If the graph shows distance vs time, and the acceleration is a change
in direction only, then the graph is a straight line sloping up, since speed
is constant.

6 0
3 years ago
Calculate the minimum average power output necessary for a person to run up a 12.0 m long hillside, which is inclined at 25.0° a
Viktor [21]

Answer:

Power, P = 924.15 watts

Explanation:

Given that,

Length of the ramp, l = 12 m

Mass of the person, m = 55.8 kg

Angle between the inclined plane and the horizontal, \theta=25^{\circ}

Time, t = 3 s

Let h is the height of the hill from the horizontal,

h=l\ sin\theta

h=12\times \ sin(25)

h = 5.07 m

Let P is the power output necessary for a person to run up long hill side as :

P=\dfrac{E}{t}

P=\dfrac{mgh}{t}

P=\dfrac{55.8\times 9.8\times 5.07}{3}

P = 924.15 watts

So, the minimum average power output necessary for a person to run up is 924.15 watts. Hence, this is the required solution.

3 0
3 years ago
Which term best describes a severe weather event characterized by heavy snowfall, strong winds, and reduced visibility?
Margaret [11]

Answer:

OC. blizzard

Explanation:

In the United States, the National Weather Service defines a blizzard as a severe snow storm characterized by strong winds causing blowing snow that results in low visibilities. ... A severe blizzard has winds over 72 km/h (45 mph), near zero visibility, and temperatures of −12 °C (10 °F) or lower.

4 0
3 years ago
PLEASE HELP ME!
Scrat [10]

Answer: If the car were to abruptly stop and the seat belts were not being worn, then the passengers in motion would continue in motion. Assuming a negligible amount of friction between the passengers and the seats, the passengers would likely be propelled from the car and be hurled into the air. Once they leave the car, the passengers becomes projectiles and continue in projectile-like motion.

Hope this is helpful!!! :)

3 0
3 years ago
A bat is flitting about in a cave, navigating via ultrasonic bleeps. Assume that the sound emission frequency of the bat is 37.5
n200080 [17]

Answer:

39.11 Hz

Explanation:

Data provided in the question:

Frequency of sound emission, f_0 = 37.5 kHz = 37500 Hz

Speed of bat, v_{bat} = 0.021 times the speed of sound

Now,

Frequency heard by bat = f_0\times(\frac{v+v_{bat}}{v-v_{bat}})

Therefore,

The Frequency heard by bat will be = 37500\times(\frac{343+0.021\times343}{343-0.021\times343})

or

Frequency heard by bat will be= 37500\times\frac{350.203}{335.797}

or

Frequency heard by bat will be = 39108.78 Hz = 39.11 Hz

5 0
3 years ago
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