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viktelen [127]
3 years ago
10

As an object fall in a gravitational field, its speed increases. This is an example of potential energy transforming into what?

Physics
1 answer:
IrinaK [193]3 years ago
5 0

Answer:

potential energy is transformed into kinetic energy

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What is the potential energy of two electrons that are separated by a distance of 3.5 x 10^-11m ?
Simora [160]

Answer:

6.58×10⁻¹⁸ J

Explanation:

Applying

E = kq²/r.................. Equation 1

Where E = potential energy, q = charge on each electron, r = distance between the electron, k = coulomb's constant.

From the question,

Given: r = 3.5×10⁻¹¹ m,

Constant: q = 1.6×10⁻¹⁹ C, k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

E = (1.6×10⁻¹⁹)²(8.99×10⁹)/(3.5×10⁻¹¹)

E = 6.58×10⁻¹⁸ J

4 0
3 years ago
a baseball is hit straight up into the air. If the initial velocity was 20 m/s, how high will the ball go?How long will it be un
AleksAgata [21]
1) The motion of the ball is an uniformly accelerated motion, with constant acceleration equal to g=-10 m/s^2 (the negative sign means it is directed towards the ground).

For an uniformly accelerated motion, we can use the following relationship:
2gh=v_f^2-v_i^2
where h is the maximum height reached by the ball, v_i = 20 m/s is its initial velocity and v_f the velocity of the ball when it reaches the maximum height. But v_f=0 (when the ball reaches the maximum height, it stops before going down, so its velocity at that moment is zero), so we can use the relationship to  calculate h, the maximum height:
h=- \frac{v_i^2}{2g} =- \frac{20 m/s)^2}{2 \cdot (-10 m/s^2)} =20 m

2) We can find the time the ball takes to return to the ground by requiring that the space covered by the ball returns to zero: 
S(t)=0
where for an uniformly accelerated motion,
S(t)=v_i t +  \frac{1}{2} gt^2 =0
By solving this, we have two solutions: one is t=0, which corresponds to the moment the player hits the ball, the second one is
t=- \frac{2 v_i}{g}=- \frac{2 \cdot 20 m/s}{-10 m/s^2}=4 s
so, the ball returns to the ground after 4 s.

3) The velocity of the ball when it returns to the ground is given by:
v(t) = v_i +gt=20 m/s + (-10 m/s^2)(4 s)=-20 m/s
where the negative sign means the ball is going downwards.
8 0
3 years ago
How does a valve cause a pressure drop in terms of the individual molecules in the liquid?
andre [41]
Opening the valve allows more of the pressurized material out. If the area is decreased, less of the pressurized material is released, and its force ends up more spread out, reducing the pressure. Opening the valve will increase volume of transfer of your liquid.
8 0
3 years ago
If a car is driving at 10 m/s and is driving for 2 minutes, what is the total distance it will
kondor19780726 [428]

Distance = (speed) x (time)

Distance = (10 meter/second) x (2 minutes)

Distance = (10 meter/second) x (2 minutes) x (60 second/minute)

Distance = (10 x 2 x 60) (meter-minute-second / second-minute)

<em>Distance = 1,200 meters</em>

4 0
3 years ago
During a rainstorm, water seeps into the ground. This process is called _____.
Andrew [12]
During a rainstorm, water seeps into the ground. This process is called INFILTRATION.

Infiltration is a part of the six process of the water cycle. It is the second part of the cycle.

The 6 processes are CONDENSATION, INFILTRATION, RUNOFF, EVAPORATION, PRECIPITATION, TRANSPIRATION.

5 0
3 years ago
Read 2 more answers
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