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77julia77 [94]
3 years ago
13

Precision measurements of the acceleration due to gravity show that the acceleration is slightly different in different location

s on Earth. Explain why the force of gravity is not exactly the same everywhere on Earths surface.
Physics
2 answers:
DochEvi [55]3 years ago
6 0
Gravity largely depends on the comparison of two objects; it's why you have the equation F= (GMm)/r^2. On Earth, you have different altitudes that, with the formula, will give different results for gravity because the radius is different everywhere. This difference on calculations, however, are seen to be miniscule. We know gravity as 9.81 m/s^2 but it might be different by thousandths or hundreds of thousandths of a decimal.
sdas [7]3 years ago
4 0

Answer:

Because Earth is not a perfect sphere.

Explanation:

The gravitational force acting between Earth (mass = M) and any object (mass = m) is

F = \frac{GMm}{r^{2}}

Where,

G = Universal gravitational constant

r = distance between center of Earth and center of the object

It is evident that the mass of Earth and object will not change with the change in location on Earth. Also value of G is also constant. The only variable is r.

We know that the Earth is not a perfect sphere it is bulged out a little around the equator and flattened near the poles because of this the Polar radius is around 21 km smaller than equatorial radius. This difference in radius creates a difference in force of gravity. Since the difference in radius is vary small the change in force is also very small.

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In SI units, what is the magnitude the net force acting on a 1,152 kg car that accelerates uniformly along a straight line from
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Answer:

Fnet = 14515.2 Newton

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

Fnet = Fapp + Fg

Where;

  • Fnet is the net force.
  • Fapp is the applied force.
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Given the following data;

Mass = 1,152 kg

Initial velocity, u = 3m/s

Final velocity, v = 17m/s

Time, t = 5 seconds

To find the magnitude of the net force;

First of all, we would determine the acceleration of the car.

Acceleration = (v-u)/t

Acceleration = (17 - 3)/5

Acceleration = 14/5

Acceleration = 2.8m/s

To find the applied force;

Fapp = mass * acceleration

Fapp = 1,152 * 2.8

Fapp = 3225.6 N

Next, we would find the force exerted on the car due to gravity.

Fg = mass * acceleration due to gravity

We know that acceleration due to gravity is equal to 9.8m/s²

Fg = 1152 * 9.8

Fg = 11289.6N

Substituting the values into the equation, we have;

Fnet = 3225.6 + 11289.6

Fnet = 14515.2 Newton

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