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77julia77 [94]
3 years ago
13

Precision measurements of the acceleration due to gravity show that the acceleration is slightly different in different location

s on Earth. Explain why the force of gravity is not exactly the same everywhere on Earths surface.
Physics
2 answers:
DochEvi [55]3 years ago
6 0
Gravity largely depends on the comparison of two objects; it's why you have the equation F= (GMm)/r^2. On Earth, you have different altitudes that, with the formula, will give different results for gravity because the radius is different everywhere. This difference on calculations, however, are seen to be miniscule. We know gravity as 9.81 m/s^2 but it might be different by thousandths or hundreds of thousandths of a decimal.
sdas [7]3 years ago
4 0

Answer:

Because Earth is not a perfect sphere.

Explanation:

The gravitational force acting between Earth (mass = M) and any object (mass = m) is

F = \frac{GMm}{r^{2}}

Where,

G = Universal gravitational constant

r = distance between center of Earth and center of the object

It is evident that the mass of Earth and object will not change with the change in location on Earth. Also value of G is also constant. The only variable is r.

We know that the Earth is not a perfect sphere it is bulged out a little around the equator and flattened near the poles because of this the Polar radius is around 21 km smaller than equatorial radius. This difference in radius creates a difference in force of gravity. Since the difference in radius is vary small the change in force is also very small.

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A runner begins from rest at the starting line and travles for 6.5 seconds, a runner reaches a speed of 13.4 m/s what is the run
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The acceleration of the runner in the given time is 2.06m/s².

Given the data in the question;

Since the runner begins from rest,

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Acceleration is simply the rate of change of the velocity of a particle or object with respect to time. Now, we can see the relationship from the First Equation of Motion

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v = u + at\\\\13.4m/s = 0 + (a * 6.5s)\\\\13.4m/s = a * 6.5s\\\\a = \frac{13.4m/s}{6.5s}\\ \\a = 2.06m/s^2

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Learn more about Equations of Motion: brainly.com/question/18486505

3 0
2 years ago
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A plane has a takeoff speed of 88.3 m/s and can accelerate at a rate of 3m/s to reach that speed. How long does the plane take t
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a = \frac{v}{t}

We have acceleration and velocity so:

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In the acceleration equation we can isolate for v and then plug it back into the other equation to solve...

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3t = v

88.3 = 3t

Divide by three and

t = 29.4 s

3 0
3 years ago
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