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77julia77 [94]
4 years ago
13

Precision measurements of the acceleration due to gravity show that the acceleration is slightly different in different location

s on Earth. Explain why the force of gravity is not exactly the same everywhere on Earths surface.
Physics
2 answers:
DochEvi [55]4 years ago
6 0
Gravity largely depends on the comparison of two objects; it's why you have the equation F= (GMm)/r^2. On Earth, you have different altitudes that, with the formula, will give different results for gravity because the radius is different everywhere. This difference on calculations, however, are seen to be miniscule. We know gravity as 9.81 m/s^2 but it might be different by thousandths or hundreds of thousandths of a decimal.
sdas [7]4 years ago
4 0

Answer:

Because Earth is not a perfect sphere.

Explanation:

The gravitational force acting between Earth (mass = M) and any object (mass = m) is

F = \frac{GMm}{r^{2}}

Where,

G = Universal gravitational constant

r = distance between center of Earth and center of the object

It is evident that the mass of Earth and object will not change with the change in location on Earth. Also value of G is also constant. The only variable is r.

We know that the Earth is not a perfect sphere it is bulged out a little around the equator and flattened near the poles because of this the Polar radius is around 21 km smaller than equatorial radius. This difference in radius creates a difference in force of gravity. Since the difference in radius is vary small the change in force is also very small.

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Answer:

Explanation:

A )

At the bottom of the circle , the potential energy of the stopper is converted into kinetic energy

1/2 m V² = mg x 2r + 1/2 mv²

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1/2  V² = g x 2r + 1/2 v²

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V² = 103.2

V = 10.16 m/s

B )

If T be the tension at the top

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mg +T = mv² / r

T =   mv²/r -mg

= m ( v²/r - g )

= .005 ( 8²/1 -g )

= .005 x 54.2

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C ) At the bottom

Net force = T  - mg , T is tension at the bottom , V is velocity at bottom

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3 0
3 years ago
(a) If a proton with a kinetic energy of 6.2 MeV is traveling in a particle accelerator in a circular orbit with a radius of 0.5
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Answer:

The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

Explanation:

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Given that,

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Using formula of acceleration

a=\dfrac{v^2}{r}

Put the value into the formula

a=\dfrac{\dfrac{1}{2}mv^2}{\dfrac{1}{2}mr}

Put the value into the formula

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a=2.32\times10^{15}\ m/s^2

We need to calculate the rate at which it emits energy because of its acceleration is

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Put the value into the formula

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Hence, The fraction of its energy that it radiates every second is 3.02\times10^{-11}.

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