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Sunny_sXe [5.5K]
3 years ago
9

a stone of mass 750 kg is thrown vertically upward with a velocity of 10m/s find the potential energy at the greatest height and

kinetic energy on reaching the ground​
Physics
1 answer:
Taya2010 [7]3 years ago
8 0

Answer:

Potential Energy at the greatest point = 37.5 J

Explanation:

Given :

Mass is 750 g

In term of kg :

Mass is 0.75 kg .

Velocity ( v ) = 10 m / sec

We have formula for kinetic energy :

K.E. = 1 / 2 m v²

Putting values now :

K.E. = 1 / 2 × 0.75 × 10 × 10

K.E. = 1 / 2 × 75 J

K.E. = 37.5 J

Since K.E . = P.E.

Thus potential energy of stone is 37.5 J .

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Answer:

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Explanation:

The period of an oscillation equation of a solid pendulum is given by:

T=2\pi \sqrt{\frac{I}{Mgd}} (1)

Where:

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Let's solve the equation (1) for I

T=2\pi \sqrt{\frac{I}{Mgd}}

I=Mgd(\frac{T}{2\pi})^{2}

Before find I, we need to remember that

T = \frac{1}{f}=\frac{1}{0.680}=1.47\: s

Now, the moment of inertia will be:

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Therefore, the moment of inertia is:

I=0.37 \: kgm^{2}

I hope it helps you!

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