Here we have to explain and predict the product of the reaction between hept-3-yne and bromine (Br₂)
The reaction between hept-3-yne and bromine produces <em>trans</em>-3,4-dibromo-3-heptene.
The reaction between the unsaturated hydrocarbon with halogen remove the unsaturation in the molecule and produces di halo compound. The reaction proceed through the formation of bromonium ion.
In this reaction as the unsaturation present in the middle of the alkyl chain i.e. hept-3-yne. The reaction will stop after the formation of di-halo compound with one double bond as shown in the figure.
The product will be exclusively trans product as the bromine is a bulky group and the formation of bromonium ion (intermediate) will be one side of the unsaturated compound.
Answer:
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The concentration of the solution reduces and the number of moles of solute isn't affected.
Data;
- V1 = 50mL
- C1 = 12.0M
- V2 = 200mL
- C2 = ?
<h3>Facts about the diluted solution</h3>
1. When the solution is diluted, the concentration changes and this time, the concentration reduces.
Using dilution formula
The concentration of the solution reduces.
2. The number of moles remains the same.
When a solution is diluted, the number of moles remains the same because there's no change in the mass of the solute.
Learn more on concentration of a solution here;
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