Answer:
Explanation:
= Mass of metal = 19 g
= Specific heat of the metal
= Temperature difference of the metal =
V = Volume of water = 150 mL =
= Density of water =
= Specific heat of the water = 4.186 J/g°C
= Temperature difference of the water =
Mass of water
Heat lost will be equal to the heat gained so we get
The specific heat of the metal is .
Answer:
Explanation:
The combustion reaction of Octane is:
To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.
We calculate the mass of Octane from the given volume and density, using the following <em>conversion factors</em>:
Now we<u> convert 1.24 gallons to mL</u>:
We <u>calculate the mass of Octane</u>:
Now we use the <em>stoichiometric ratios</em> and <em>molecular weights</em> to <u>calculate the mass of CO₂ and H₂O</u>: