Answer:
Element symbol Cu
Number of protons 29
Number of electrons 28
Explanation:
To get the element symbol, we need the name of the element. To correctly identify the name of the element, we need the proton number.
Now the mass number is 65 and the number of neutrons is 36. The number of protons is this the mass number minus the number of neutrons. This equals 65 - 36 = 29 protons.
The element with 29 protons is copper Cu.
Now to get the number of electrons, for an electrically neutral atom , the number of electrons equals the number of protons. But here, the atom is not electrically neutral anymore as it has now formed a univalent positive ion of +1.
To form a positive ion, you have to do so by losing electrons. The atom in question here has just lost one electron. Thus, our of the 29, it is left with only 28 electrons.
Answer:
<h3>The answer is option C</h3>
Explanation:
The mass of a substance when given the density and volume can be found by using the formula
<h3>mass = Density × volume</h3>
From the question
volume of liquid = 15 mL
density = 2.5 g/mL
We have
mass = 15 × 2.5
We have the final answer as
<h3>37.5 g</h3>
Hope this helps you
Molarity of solution = 1.6 M
<h3>Further explanation</h3>
Given
40 g NaOH
6 L solution
Required
Steps to solve the problem of molarity
Solution
No additional information about the question.
If you want to make the solution above, then we just need to put the existing NaOH (40 g) into 6 L of water, then do the stirring (in a warm temperature above the hot plate will speed up the NaOH dissolving process)
But if you want to know the molarity of a solution, then
- 1. we calculate the moles of NaOH

MW(molecular weight) of NaOH=
Ar Na+ Ar O + Ar H
23 + 16 + 1 = 40 g/mol
so mol NaOH :


Gas chromatography is a type of <span>chromatography that is usually used in analytic chemistry in order to analyze and separate the compounds that can be vaporized without decomposition.
Based on this:
</span><span>Gas chromatography can be useful in determining the chemical composition of paint.</span>