Answer:
V₂ = 111.3 mL
Explanation:
Given data:
Initial volume of gas = 50.0 mL
Initial temperature = standard = 273.15 K
Final volume = ?
Final temperature = 335 °C (335+273.15 = 608.15 K)
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 50.0 mL ×608.15 K / 273.15 k
V₂ = 30407.5 mL.K / 273.15 K
V₂ = 111.3 mL
Ethane can be turned into its carboxylic acid form called the ethanoic acid by a series of steps. First chlirinate it in the presence of light. Then, add potassium hydroxide to get an alcohol. Finally, adding KMnO4 to oxidize it to a carboxylic acid. The equations are as follows:
C2H6 + Cl2 ---> C2H5Cl + HCl
C2H5Cl+KOH-> C2H5OH+ KCl.
C2H5OH ----KMnO4 ---> CH3COOH.
Answer:
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Explanation:
