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3 years ago

How many molecules are there in 5.9 moles of NaCl?

Chemistry

1 answer:

choli [55]3 years ago

3 0

The number of molecules= 3.55 x 10²⁴

<h3>Further explanation</h3>

Given

5.9 moles of NaCl

Required

The number of molecules

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

So for 5.9 moles :

= 5.9 x 6.02 x 10²³

= 3.55 x 10²⁴

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The specific heat of copper metal is 0. 385 J/(g °C). How much energy must be added to a 35. 0-gram sample of copper to change t

Rus_ich [418]

The amount of heat required for changing the temperature of copper has been 606 J. Thus, option B is correct.

Specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.

The heat required to raise the temperature has been expressed as:

$\rm Heat=mass\;\times\;specific\;heat\;\times\;Change\;in\;temperature$

<h3>Computation for the heat energy required</h3>

The given specific heat of copper has been $\rm 0.385\;J/g^\circ C$

The mass of copper has been, $\rm 35\;g$

The initial temperature of copper has been, $\rm 20^\circ C$

The final temperature of copper has been, $\rm 65^\circ C$

The change in temperature has been, $\Delta T$

$\Delta T=\text{Final\;temperature-Initial\;temperature}\\\Delta T =65^\circ \text C-20^\circ \text C\\\Delta T=45^\circ \text C$

Substituting the values for the heat required as:

$\rm Heat=35\;g\;\times\;0.385\;J/g^\circ C\;\times\;45^\circ C\\Heat=606\;J$

The amount of heat required for changing the temperature of copper has been 606 J. Thus, option B is correct.

Learn more about specific heat, here:

brainly.com/question/2094845

7 0

2 years ago

2 moles of sodium phosphate reacts with 3 moles of

miss Akunina [59]

Answer: 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of calcium chloride

Explanation:

The balanced chemical equation is:

$2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2$

According to stoichiometry :

2 moles of $Na_3PO_4$ require 3 moles of $CaCl_2$

Thus both are limiting reagent as both will limit the formation of product.

As 2 moles of $Na_3PO_4$ reacts with 3 moles of $CaCl_2$ give = 6 moles of $NaCl$

Thus 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of calcium chloride

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3 years ago

0.444 mol C2H5OH= how many molecules

brilliants [131]

Explanation:

hope it make sense to u :)

8 0

3 years ago

The normal boiling point of a liquid is 282 °C. At what temperature (in °C) would the vapor pressure be 0.500 atm? (∆Hvap = 28.5

NNADVOKAT [17]

For a normal boiling point of a liquid is 282 °C, the temperature is mathematically given as

T2=181.55°C\

<h3> What temperature (in °C) would the vapor pressure be 0.500 atm? </h3>

Generally, the equation for the gas is mathematically given as

ln(p1/p2)=dHvap/R(1/T2-1/T1)

Therefore

ln(1/0.26)=23500/8.214(1/T2-1/555)

T2=181.55^C

In conclusion

T2=181.55°C