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3 years ago

How many molecules are there in 5.9 moles of NaCl?

Chemistry

1 answer:

choli [55]3 years ago

3 0

The number of molecules= 3.55 x 10²⁴

<h3>Further explanation</h3>

Given

5.9 moles of NaCl

Required

The number of molecules

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

So for 5.9 moles :

= 5.9 x 6.02 x 10²³

= 3.55 x 10²⁴

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Answer:

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Explanation:

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4 years ago

The Ksp of yttrium iodate, Y(IO3)3 , is 1.12×10−10 . Calculate the molar solubility, s , of this compound.

torisob [31]

Answer:

1.427x10^-3mol per L

Explanation:

$Y(IO_{3} )_{3} ---- Y^{3+} +IO_{3} ^{3-}$

I could use ⇌ in the math editor so I used ----

from the question each mole of Y(IO3)3 is dissolved and this is giving us a mole of Y3+ and a mole of IO3^3-

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so in conclusion

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3 years ago

A 10.0 L flask at 318 K contains a mixture of Ar and CH4 with a total pressure of 1.040 atm. If the mole fraction of Ar is 0.715

andrey2020 [161]

Answer:

$w_{Ar}=0.814$

Explanation:

Hello,

In this case, given the temperature, volume and total pressure, we can compute the total moles by using the ideal gas equation:

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And the moles of methane:

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$w_{Ar}=\frac{m_{Ar}}{m_{Ar}+m_{CH_4}}=\frac{0.29mol*\frac{40g}{1mol} }{0.29mol*\frac{40g}{1mol}+0.12mol*\frac{16g}{1mol}} \\\\w_{Ar}=0.814$

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3 years ago

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