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3 years ago

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Bending is defined as? A. the application of a load tending to distort a member in one direction. B. the application of opposing

load with a very narrow specific area. C. the application of pushing load data application of pulling loads. E.application of twisting a load.

1 answer:

amm18123 years ago

4 0

Hi how are you today

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Some soil has a discharge rate of 0.1 L/s, an area of 11 m2, and a hydraulic head that is given empirically by the function H =

Artist 52 [7]

Answer:

3.03 * 10 ⁻⁴ m/s

Explanation:

see attached picture for explanation.

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3 years ago

The article "Display of Health Risk Behaviors on MySpace by Adolescents"† described a study in which researchers looked at a ran

nadya68 [22]

Answer:

True. 18-year old teenagers that practice some sport or have a hobby have less references to substance abuse or violence.

Explanation:

When someone practices a certain sport, he/she is occupied with its sport, also, sports encourage responsability, discipline and takes most of the person´s time and energy. People who doesn´t practice sports or have any hobby have more idle time and is always looking for something to take away the boredom. Most of the cases they start doing drugs or start having violent episodes because is what´s more handful and gives them the dopamine that the sport is not giving them (because they don´t practice any).

This is way the display of sports or hobbies involvements is associated with decreased references to risky behavior.

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3 years ago

What type of screwdriver requires the use of a hammer or mallet?

masya89 [10]

Answer:

Slot screw driver can be used that way but I wouldn't recommend it

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3 years ago

An 18-in.-long titanium alloy rod is subjected to a tensile load of 24,000 lb. If the allowable tensile stress is 60 ksi and the

Vilka [71]

Answer:

Required Diameter = 302.65 inches

Explanation:

We are given;

Allowable tensile stress = 60 ksi

Weight of tensile load = 24,000 lb

Elongation = 0.05 in

Original length = 18 in

We'll need to check the diameters under stress and strain.

Now, we know that the formula for stress is;

Stress = Force/Area

Thus,

Area = Force/stress

So for this stress, area required is;

A_req = 24000/60 = 4000 in²

So let's find the required diameter here.

Area = πd²/4

So, 4000 = πd²/4

(4000 x 4)/π = d²

d² = 5092.96

Required diameter here is;

d = √5092.96

d = 71.36 in

For Strain;

Formula for strain is;

Strain = stress/E

We are given E = 120 ksi

stress = P/A = 24,000/A

strain = elongation/original length = 0.05/18 = 0.00278

Thus;

0.00278 = P/(A•E)

0.00278 = 24000/(120 x A)

Making A the subject to obtain;

A = 24000/(120 x 0.00278)

A_required = 71942 in²

Area = πd²/4

So, 71942 = πd²/4

(71942 x 4)/π = d²

d² = 91599.4

Required diameter here is;

d = √91599.4

d = 302.65 in

The larger diameter is 302.65 inchesand it's therefore the required one.

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4 years ago

Bars A and B have cross-sectional areas of 400 m2 and a modulus of elasticity of 200 GPa. A gap exists between bar A and the rig

NISA [10]

Answer:

axial stress in bar B = 25Mpa.

Deformation of bar A = 0.4mm.

Explanation:

PS: Kindly check the attached picture for the diagram showing the two bars that is to say the bar A and the bar B.

So, we are given the following data or information or parameters which we are going to use in solving this particular question or problem. Here they are;

The cross-sectional areas of Bars A and B = 400 mm2, the modulus of elasticity of bar A and bar B = 200 GPa, applied force = 10kN.

STEP ONE: The first step is to determine or calculate the axial stress in bar B. Therefore,

Axial stress in bar B = 10 × 10³ ÷ 400 × 10⁻⁶ = 25 Mpa.

STEP TWO: The second step here is to determine or calculate the deformation of bar A. Therefore,

The deformation of bar A = 20 × 10³ ×1.5 ÷ 400 × 10⁻⁶ × 200 × 10³ = 0.375 mm.

3 0

3 years ago