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2 years ago

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Bending is defined as? A. the application of a load tending to distort a member in one direction. B. the application of opposing

load with a very narrow specific area. C. the application of pushing load data application of pulling loads. E.application of twisting a load.

1 answer:

amm18122 years ago

4 0

Hi how are you today

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Free ideas free points. You will be reported for answering "no" or I don't know

KengaRu [80]

Answer:

Here are some cool ideas that you could do

-Zero fuel aircraft

-Advanced Space Propulsion Technologies

-Smart Automation and Blockchain

These are some things I've been working on for a few years lol, maybe you will have more luck

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3 years ago

Which band has an average of $3.58 per hour of parking?

Minchanka [31]

C it would be c because that has more and the others have less

6 0

2 years ago

Teresa is emotionally volatile, particularly with friends and boyfriends. She is extremely dramatic about even the smallest disa

Ilia_Sergeevich [38]

Answer: Borderline personality Disorder.

Explanation: This is a type of mental disorder which could affects mood, behavior and relationships.

Its symptoms includes unstable emotions, sense of insecurity, worthlessness, and impulsivity.

This condition can not be cured, but treatments such as therapies, medication (in some cases) could help.

4 0

3 years ago

Typical noise associated with failed cv joint

igor_vitrenko [27]

Answer:

A worn inner CV joint often makes a clunking noise during starts and stops.

3 0

2 years ago

Refrigerant 134a enters the evaporator of a refrigeration system operating at steady state at -16oC and a quality of 20% at a ve

Dmitry [639]

Answer:

mass flow rate = 0.0534 kg/sec

velocity at exit = 29.34 m/sec

Explanation:

From the information given:

Inlet:

Temperature $T_1 = -16^0\ C$

Quality $x_1 = 0.2$

Outlet:

Temperature $T_2 = -16^0 C$

Quality $x_2 = 1$

The following data were obtained at saturation properties of R134a at the temperature of -16° C

$v_f= 0.7428 \times 10^{-3} \ m^3/kg \\ \\ v_g = 0.1247 \ m^3 /kg$

$v_1 = v_f + x_1 ( vg - ( v_f)) \\ \\ v_1 = 0.7428 \times 10^{-3} + 0.2 (0.1247 -(0.7428 \times 10^{-3})) \\ \\ v_1 = 0.0255 \ m^3/kg \\ \\ \\ v_2 = v_g = 0.1247 \ m^3/kg$

$m = \rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ m = \dfrac{1}{0.0255} \times \dfrac{\pi}{4}\times (1.7 \times 10^{-2})^2\times 6 \\ \\ \mathbf{m = 0.0534 \ kg/sec}$

$\rho_1A_1v_1 = \rho_2A_2v_2 \\ \\ A_1 =A_2 \\ \\ \rho_1v_1 = \rho_2v_2 \\ \\ \implies \dfrac{1}{0.0255} \times6 = \dfrac{1}{0.1247}\times (v_2)\\ \\ \\\mathbf{\\ v_2 = 29.34 \ m/sec}$

3 0

2 years ago