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sergey [27]
3 years ago
15

Explain why Chloe's design needs to be redone in the following scenario, and recommend the techniques she needs to include in he

r sketches.
Chloe has drawn a design of a new supermarket She has added all of her detail to one isometric sketch. The design was not done to scale, and the construction team is not sure how large the
building will be once it is complete.
Engineering
2 answers:
Alenkinab [10]3 years ago
7 0

Answer:

She believes he's weak and won't do what needs to be done to become a king.

Explanation:

She says ('I fear thy nature') and calls him 'too full o' th' milk of human kindness' which reflects that she feels his kindness makes him weak and may prevent him from proceeding the plan. Thus, she manipulates him to keep his kindness aside and do what she wishes him to do. She rather belittles him to get her purpose solved and

Debora [2.8K]3 years ago
3 0

Answer:

The correct answer includes that her sketch should also include an orthographic view. She also needs to incorporate ratios to proportions so the team will know the scale of the design. She can use customary units for her measurements, as well as an engineer’s scale and a computer program to assist her with the dimensions.

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Steam at 40 bar and 500o C enters the first-stage turbine with a volumetric flow rate of 90 m3 /min. Steam exits the turbine at
a_sh-v [17]

Answer:

(a) 62460 kg/hr

(b) 17,572.95 kW

(c) 3,814.57 kW

Explanation:

Volumetric flow rate, G = 30 m³ / 1 min => 90 / 60 => 1.5

Calculate for h₁ , h₂ , h₃

h₁ is h at P = 40 bar, 500°C => 3445.84 KJ/Kg

Specific volume steam, ц = 0.086441 m³kg⁻¹

h₂ is h at P = 20 bar, 400°C => 3248.23 KJ/Kg

h₃ is h at P = 20 bar, 500°C => 3468.09 KJ/Kg

h₄ is hg at P = 0.6 bar from saturated water table => 2652.85 KJ/Kg

a)

Mass flow rate of the steam, m = G / ц

m = 1.5 / 0.086441

m = 17.35 kg/s

mass per hour is m = 62460 kg/hr

b)

Total Power produced by two stages

= m (h₁ - h₂) + m (h₃ - h₁)

= m [(3445.84 - 3248.23) + (3468.09 - 2652.85)]

= m [ 197.61 + 815.24 ]

= 17.35 [1012.85]

= 17,572.95 kW

c)

Rate of heat transfer to the steam through reheater

= m (h₃ - h₂)

= 17.35 x (3468.09 - 3248.23)

= 17.35 x 219.86

= 3,814.57 kW

8 0
3 years ago
write down your own definition of Engineering, preferably in 4-5 sentences. Maximum of 150 words for your definition???.​
ollegr [7]

Answer:

A charge q1=7.0mc is located at the origin and a second charge q2=-5.0mc is located on the x axis, 0.3m the origin find the electric field at the point p which he's coordinates (0,0.40)m

4 0
3 years ago
Two parallel Rivers (A and B) are separated by confined and unconfined aquifer estimate the RATE of seepage of river A to River
gizmo_the_mogwai [7]

Answer:

Explanation:

A confined aquifer is one that's impermeable and does not allow seepage's  of water through it.

An unconfined aquifer is a body of water that has permeable membranes which allows passage of water through it.

There will be little or no transmission of water trough these bodies of water.

3 0
3 years ago
A rotating beam is subject to an alternating stress of 48 kpsi and a mean stress of 24 kpsi. The ultimate strength of the materi
Alisiya [41]

Answer:

goodman = 0.694

life of beam = 211597

Explanation:

alternating stress = 48 kpsi

mean stress = 24 kpsi

ultimate strength = 100 kpsi

endurance limit = 40 kpsi

goodman:

= \frac{mean stress}{ultimate stress} +\frac{alternating stress}{endurance limit} =\frac{1}{N}

= \frac{24}{100} +\frac{48}{40} =\frac{1}{N}

= 0.24 + 1.2 = \frac{1}{N}

N = 1/1.44

N = 0.694

2. check attachment for diagram

Log(N)-3/3 = log90 - log48/log90 - log40

Log(N)-3/3 = 0.77517

Log N = 5.325509

N = 10^(5.325509)

N = 211597

6 0
2 years ago
Problem 2: Sieve Analysis and Soil Gradation
Marina CMI [18]

<u>Explanation:</u>

% Gravel = 100 - 72% = 28%

% Sand = 100 - 28 - 15 = 57%

% Fires = 100 - 0 - 28 - 57 = 15%

\begin{aligned}&D_{n} \cdot 0.03 \quad ; \quad D_{x}=1.1 \quad ; \quad D_{0}=3.3\\&C_{u}=\frac{D_{60}}{D_{10}}=\frac{3.3}{0.03}=110\\&C_{c}=\frac{D_{30}^{2}}{D_{0} \cdot D_{0}}=\frac{1.1^{2}}{3.3 \times 0.03}=12.22\end{aligned}

The soil is poorly graded soil.

6 0
3 years ago
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