An inverting amplifier with +11 V supply voltages normally has a sinusoidal output of 10 Vpp. When checking the circuit with an
oscilloscope, you find that the output is 0 V. Which of the following could account for this problem? A) RF is shorted by a solder bridge.B) R1 is open. C) Vi = 0 D) All of the above
1 answer:
Answer:
D) All of the above
Explanation:
To understand why we need to study case by case:
A) RF is shorted by a solder bridge: If RF is shorted, the output is going to be at the same potential that the inverting input due to a virtual short circuit (the inverting input is 0V because the non-inverting input is GND)
B) R1 is open: If R1 is open there is not input voltage to amplify therefore the output is 0V
C) Vi = 0: If Vi is equal zero there is not input voltage to amplify therefore the output is 0V
Note: Because there's is not schematic we assume the one in the picture down below, our logical explanation is complemented with a simulation that matches our results. For our case the amplifier requires a positive and negative supply, so we use an inverting amplifier with +11 V and -11V power supply.
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