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3 years ago

An unbalanced force of 40. newtons keeps a

Physics

2 answers:

Pachacha [2.7K]3 years ago

4 0

(4) 4.0 m/s is the correct answer

faltersainse [42]3 years ago

4 0

Answer:

4.0 m/s

Explanation:

Unbalanced force(F) = 40N

Mass(m) = 5.0kg

Radius(r) = 2.0m

Speed(v)= ???

F = (mv^2)/r

Make v the subject of the formula

mv^2 = Fr

v^2 = Fr / m

v = √Fr/m

v = √(40*2)/5

v = √80/5

v = √16

v = 4.0 m/s

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Answer:

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Explanation:

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3 years ago

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Suppose that the Millennium Falcon orbits the Death Star 20,000m above the Star’s surface. Calculate the circular orbit velocity

Nataly [62]

Answer:

18.4 m/s

Explanation:

The gravitational force between the Death Star and the Millenium Falcon is equal to the centripetal force that keeps the Millenium Falcon in circular orbit:

$G\frac{Mm}{(R+h)^2}=m\frac{v^2}{R+h}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$M=5.1\cdot 10^{17} kg$ is the mass of the planet

$m=1.36\cdot 10^6 kg$ is the mass of the Millennium Falcon

$v$ is the orbital velocity of the Millennium Falcon

$R=\frac{160,000 m}{2}=80,000 m$ is the radius of the Death Star

$h=20,000 m$ is the altitude of the Millennium Falcon above the planet's surface

Solving the equation for v, we find the orbital velocity:

$v=\sqrt{\frac{GM}{R+h}}=\sqrt{\frac{(6.67\cdot 10^{-11})(5.1\cdot 10^{17} kg)}{80,000 m+20,000 m}}=18.4 m/s$

5 0

3 years ago

By what potential difference must a proton [m_0 = 1.67E-27 kg) be accelerated to have a wavelength lambda = 4.23E-12 m? By what

Vinil7 [7]

Explanation:

1. Mass of the proton, $m_p=1.67\times 10^{-27}\ kg$

Wavelength, $\lambda_p=4.23\times 10^{-12}\ m$

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

$\lambda=\dfrac{h}{\sqrt{2m_pq_pV}}$

$V=\dfrac{h^2}{2q_pm_p\lambda^2}$

$V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 1.67\times 10^{-27}\times (4.23\times 10^{-12})^2}$

V = 45.83 volts

2. Mass of the electron, $m_p=9.1\times 10^{-31}\ kg$

Wavelength, $\lambda_p=4.23\times 10^{-12}\ m$

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

$\lambda=\dfrac{h}{\sqrt{2m_eq_eV}}$

$V=\dfrac{h^2}{2q_em_e\lambda^2}$

$V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 9.1\times 10^{-31}\times (4.23\times 10^{-12})^2}$

$V=6.92\times 10^{34}\ V$

V = 84109.27 volt

Hence, this is the required solution.

7 0

4 years ago

A stone is dropped into water from a bridge 52 m above the water's

dusya [7]

Answer:

Its final velocity and how much time it takes to reach the water

Explanation:

The motion of the stone is a uniformly accelerated motion, so we can use the following suvat equation to determine its final velocity:

$v^2-u^2=2as$

where

v is the final velocity

u = 0 is the initial velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity

s = 52 m is the distance covered during the fall

Solving for v,

$v=\sqrt{u^2+2as}=\sqrt{0^2+2(9.8)(52)}=31.9 m/s$

We can also find how much time it takes to reach the water, using the equation

$v=u+at$

where

v = 31.9 m/s is the final velocity

u = 0 is the initial velocity

$a=g=9.8 m/s^2$

t is the time

And solving for t,

$t=\frac{v-u}{a}=\frac{31.9-0}{9.8}=3.26 s$

3 0

4 years ago