The ionization energy of 
is 
.
<h3>What is ionization energy?</h3>
It is the energy needed to remove one electron from a neutral atom, which results in the formation of an ion.
The measurement is based on an isolated atom in its gaseous phase and is often expressed in kJ/mol.
b) Atom is ionized when the electron is completely removed from its electron cloud (so it being moved from first, 
to the infinity's shell and 
), and now the equation can be written as
So the ionization energy is affected by the charge of the nucleus and the general formula can be represented as:
and as 
The 
has an atomic number Z=5, therefore using the formula when 
=1, we get
The ionization energy of is .
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Answer:
Equilibrium shifts left making more NO2
Explanation:
In Le Chatlier's Principle, increase in volume shifts equilibrium to side with more moles so... there's 2 moles on left and 1 mole on right, so equilibrium shifts to left making more NO2
Answer:
The balance reaction is C6H12O6+6O2=6CO2+6H2O
Explanation:
The reaction mentioned above is the reaction of cellular respiration.In this reaction glucose molecule reacts with oxygen to generate carbon dioxide,water and energy in form of ATP.
In the left side there are 6 carbon atoms,12 hydrogen atoms and 18 oxygen atoms and the same number of carbon,hydrogen and oxygen is present in the right side of the reaction mentioned above.Thus the reaction can be balanced.
7.22 moles of C2H6. Since there are 2 carbon atoms per C2H6, we must multiply the number of moles of C2H6 by 2 to get the number of moles of Carbon which is 14.4 or 14 if using two sig figs.
Answer:
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Explanation:
The lowering of the freezing point of a solvent is a colligative property ruled by the formula:
Where:
- ΔTf is the lowering of the freezing point
- Kf is the molal freezing constant of the solvent: 1.86 °C/m
- m is the molality of the solution
- i is the van't Hoff factor: the number of particles (ions) per unit of ionic compound.
<u />
<u>a) molality, m</u>
- m = number of moles of solute/ kg of solvent
- number of moles of CaI₂ = mass in grams/ molar mass
- number of moles of CaI₂ = 25.00g / 293.887 g/mol = 0.0850667mol
- m = 0.0850667mol/1.25 kg = 0.068053m
<u>b) i</u>
- Each unit of CaI₂, ideally, dissociates into 1 Ca⁺ ion and 2 I⁻ ions. Thus, i = 1 + 2 = 3
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<u>c) Freezing point lowering</u>
- ΔTf = 1.86 °C/m × 0.068053m × 3 = 0.3797ºC ≈ 0.380ºC
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