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podryga [215]
3 years ago
8

What did the results of photoelectric-effect experiment establish?

Physics
2 answers:
Bond [772]3 years ago
7 0

Answer:

Thanks For Points Mark Me Brainliest Please

Explanation:

Electrons are emitted as soon as low-intensity, high-frequency light hits a metal surface.

A. Is It

TEA [102]3 years ago
6 0

Answer: I think the answer would be A. Electrons are emitted as soon as low intensity, high frequency light hits a metal surface. Byee.

-MrBeast

Explanation:

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Iron's ability to rust is not a physical property because
gtnhenbr [62]
The answer should be c
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Give reason standard physical quantity is used for correct measurement of the given body​
PtichkaEL [24]

Answer:

Physical quantities are the substances which can be measured. By measuring physical quantities, we can measure the mass, weight and other physical properties

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How to find aceleration
lions [1.4K]

Answer:

a=\frac{v_{f}-v_{i}}{t_{f}-t_{i}}

Explanation:

Formula for AVERAGE acceleration

a=\frac{v_{f}-v_{i}}{t_{f}-t_{i}}

v_{f} is Final Velocity

v_{i} is Initial Velocity

t_{f} is Final Time

t_{i} is Initial Time

Most of the time, the initial time will be 0, so you won't have to subtract.

5 0
3 years ago
According to the law of refraction, light passing from air into a piece of glass at an angle of 30 degrees will cause the light
pantera1 [17]

Answer:

bend toward the normal line

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When light passes from a less dense to a more dense substance, (for example passing from air into water), the light is refracted (or bent) towards the normal.   In your question the light is moving from rarer to denser medium

4 0
4 years ago
a concave lens creates a virtual image at -47.0 cm and a magnification of +1.75. what is the focal length?
Lilit [14]

The focal length of given concave lens will be -26.85 cm

The height of an image to the height of an object is the ratio that is used to determine a lens' magnification. Additionally, it is provided in terms of object and image distance. It is equivalent to the object distance to image distance ratio.

Given  concave lens creates a virtual image at -47.0 cm and a magnification of +1.75.

We have to find focal length

The focal length can be found out by following way:

Magnification = m = +1.75

m = hi/h

hi = -47 cm

1.75 = -47/h

h = -26.85 cm

So the focal length of given concave lens will be -26.85 cm

Learn more about magnification factor here:

brainly.com/question/6947486

#SPJ10

8 0
2 years ago
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