Well for one, A LOT of heat (or if you wanna call it energy) is being released from the mixture and the container itself starts to heat up and you can DEFINITELY feel the heat. EXO: Outside, exterior. THERMIC: Heat, something to describe hot stuff (I guess).
SO you can say it heats up the outside container and occasionally will produce steam or foam (DEPENDING ON WHAT YOU MIX)
Boyle's law gives the relationship between pressure of a gas and volume of gas.
It states that at constant temperature, pressure of gas is inversely proportional to volume of gas.PV = k
where P - pressure V- volume and k - constant
P1V1 = P2V2
since the gas occupies the volume of the container, volume of gas is taken as volume of container.
100kPa x 5.0 L = 50 kPa x V
V = 10.0 L
Answer is C.
Answer:
Aluminum
Explanation:
Because there's no other element that has this exact electron configuration
Answer:
Albedo
Explanation:
Usually when we talk about uneven heating of the Earth's surface we are discussing convection. The uneven heating results in some of the atmosphere to be warmer than other parts and changes in volume and pressure which result in updrafts and can cause thunderstorms and other violent weather.
The cause of this is the reflectiveness of the surface of the Earth at that point (the albedo) and the angle that the sun's rays strike it at. A field covered with snow and ice is going to be much more reflective than a black top asphalt parking lot. As such the parking lot absorbs much more shortwave radiation from the sun and gets much warmer.
Answer:
Explanation:
Molarity of NaOAc needed
Using the Henderson-Hasselbalch Equation calculate base molarity needed given [HOAc] = 1.00M and pKa(NaOAc) = 4.75 and [HOAc] = 1.00m.
pH = pKa + log [NaOAc]/[HOAc]
5.00 = 4.75 + log[NaOAc]/[1.00M]
5.00 - 4.75 = log [NaOAc] - log[1.00M]
log [NaOAc] = 0.25 => [NaOAc] = 10⁰·²⁵ M = 1.78
Given 10ml of HOAc, how much (ml) 1.78M NaOAc to obtain a buffer pH of 5.00.
Determine Volume of Base Needed
(M·V)acid = (M·V)base => V(base) = (M·V)acid / (M)base
Vol (NaOAc) needed = (1.00M)(0.010L)/(1.78M) = 0.0056 liter = 5.6 ml.
Checking Results:
5.00 = 4.75 + log [1.78M]/[1.00M] = 4.75 + 0.25 = 5.00 QED.