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2 years ago

Fusion is a type of _____. chemical reaction nuclear reaction physical reaction

Chemistry

2 answers:

bezimeni [28]2 years ago

8 0

Fusion is a type of <u>n</u><u>u</u><u>c</u><u>l</u><u>e</u><u>ar</u><u> </u><u>reaction</u><u> </u>....

STALIN [3.7K]2 years ago

5 0

Answer:

b) nuclear reaction

Explanation:

<h2>#hope....( no need brainliest) give the above answer</h2>

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When a solid with a mass of 53.78 g is added to 50.0 ml of water in a graduated cylinder, the volume increases to 56.4 ml. Calcu

Bad White [126]

Answer:

<h3>The answer is 8.40 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

volume = final volume of water - initial volume of water

volume = 56.4 - 50 = 6.4 mL

We have

$density = \frac{53.78}{6.4} \\ = 8.403125$

We have the final answer as

Hope this helps you

3 0

2 years ago

2Ni(OH) → Ni2O + H2O <br> How many moles of water forms from 4.20 mol of nickel (I) hydroxide?

butalik [34]

Answer:

2.1 moles of water formed.

Explanation:

Given data:

Moles of water formed = ?

Moles of Ni(OH) = 4.20 mol

Solution:

Chemical equation:

2Ni(OH) → Ni₂O + H₂O

Now we will compare the moles of Ni(OH) with water.

Ni(OH) : H₂O

2 : 1

4.20 : 1/2×4.20 = 2.1 mol

2.1 moles of water formed.

5 0

2 years ago

Please help me and explanation would be really awesome thank you!

valentina_108 [34]

Answer:

So the answer would be 10 moles

Explanation:

1) Start with the molecular formula for water: $H_{2} O!$

2) If there are 10 moles of water use a mole ratio to calculate the moles of oxygen it would produce.

(This question is... interesting... since they chose an element that is diatomic in free state so It could TECHNICALLY be two answers, moles of O or moles of $O_{2}$ )

The mole ratio is 1 moles of $H_{2}O$ to 1 moles of O. This is because the coefficient for oxygen in water is simple 1, so the ratio is 1:1.

3) that means if 10 moles of water decompose, they decompose into 10 moles of $H_{2}$ and 10 moles of O.

Extra:

About what I was saying before about the question being slightly interesting:

10 moles of pure oxygen is produced but free state oxygen exists as $O_{2}$ so it could possibly be 10 OR 5! However, notice it says elements. This leads me to believe the answer is 10 (monatomic oxygen) instead of 5 (free state/diatomic oxygen).

I hope this helps!

4 0

2 years ago

A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at

Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0

2 years ago

Ok so I have 3 beakers of clear liquid each holding a different substance, Water, Magnesium Sulphate and Sodium Carbonate how ca

nataly862011 [7]

For water you could add oil..ex: cooking oil separates form water because water is heavier than oil.

For Magnesium Sulfate you could add Sodium Carbonate..ex: Sodium Carb reacts to Mg Sulfate adding a darker hue to the liquid and adding a lot of bubbles.

For Sodium Carbonate you could add Sulfuric Acid..ex: Sulfuric Acid would add a reaction to the Sodium Carb that would resembling water boiling

H0P3 It H3LPS :)

7 0

3 years ago