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3 years ago

What's computer software, give the types of computer software with 5 examples each

Physics

1 answer:

Natasha_Volkova [10]3 years ago

4 0

Answer:

The system software is a collection of programs designed to operate, control, and extend the processing capabilities of the computer itself. System software serves, the interface between the hardware and the end users. Some examples of system software are Operating System, Compilers, Interpreter, Assemblers.

Explanation:

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A 2-kg box is pushed by a force of 4 N for 2 seconds. It has an initial velocity vo = 2 m/s to the right. NOTE: Since this probl

IRISSAK [1]

Answer:

Kf= 36 J

W(net) = 32 J

Explanation:

Given that

m = 2 kg

F= 4 N

t= 2 s

Initial velocity ,u= 2 m/s

We know that rate of change of linear momentum is called force.

F= dP/dt

F.t = ΔP

ΔP = Pf - Pi

ΔP = m v - m u

v= Final velocity

By putting the values

4 x 2 = 2 ( v - 2)

8 = 2 ( v - 2)

4 = v - 2

v= 6 m/s

The final kinetic energy Kf

Kf= 1/2 m v²

Kf= 0.5 x 2 x 6²

Kf= 36 J

Initial kinetic energy Ki

Ki = 1/2 m u²

Ki= 0.5 x 2 x 2²

Ki = 4 J

We know that net work is equal to the change in kinetic energy

W(net) = Kf - Ki

W(net) = 36 - 4

W(net) = 32 J

7 0

3 years ago

Please help, very confused!

PtichkaEL [24]

D. the last choice because the info above tells u so

4 0

3 years ago

Read 2 more answers

Starting from rest, a small block of mass m slides frictionlessly down a circular wedge of mass M and radius R which is placed o

guapka [62]

Answer:

Part a)

$V = \sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

$v = \frac{M}{m}\sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

Part b)

Since on the block wedge system there is no external force in horizontal direction so the Center of mass will not move in horizontal direction but in vertical direction it will move

so displacement in Y direction is given as

$y_{cm} = \frac{mR}{m + M}$

Explanation:

PART A)

As we know that there is no external force on the system of two masses in horizontal direction

So here the two masses will have its momentum conserved in horizontal direction

So we have

$mv + MV = 0$

Also we know that here no friction force on the system so total energy will always remains conserved

So we have

$\frac{1}{2}mv^2 + \frac{1}{2}MV^2 = mgR$

now we have

$\frac{1}{2}m(\frac{MV}{m})^2 + \frac{1}{2}MV^2 = mgR$

$\frac{1}{2}MV^2(\frac{M}{m} + 1) = mgR$

so we have

$V = \sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

and another block has speed

$v = \frac{M}{m}\sqrt{\frac{2\frac{m}{M}gR}{(\frac{M}{m} + 1)}}$

Part b)

Since on the block wedge system there is no external force in horizontal direction so the Center of mass will not move in horizontal direction but in vertical direction it will move

so displacement in Y direction is given as

$y_{cm} = \frac{mR}{m + M}$

7 0

3 years ago

A bullet of .05 kg is fired into a block of wood. Knowing that the bullet left the gun with a muzzle velocity of 350. m/s, and t

Lunna [17]

We know, Impulse of a body is change in momentum.

Also, the final velocity of wood block is 0 m/s.

So, Impulse = Final Momentum - Initial Momentum

Impulse = 0 - ( 0.05 kg × 350 m/s )

Impulse = - 17.5 kg m/s

Therefore, the impulse exerted by the wood on the bullet is -17.5 kg m/s .

6 0

3 years ago

A car of mass 940.0 kg accelerates away from an intersection on a horizontal road. When the car speed is 42.5 km/hr (11.8 m/s),

MAVERICK [17]

Answer:

0.39 $m/s^2$

Explanation:

Parameters given:

Mass of car, m = 940 kg

Speed of car, v = 11.8 m/s

Power supplied by engine, P = 4300 W

To get the acceleration, we must define the relationship between Power and velocity.

Power, P, is given in terms of velocity, v, as:

P = F * v

where F = force

This is because Power is given as:

$P = \frac{E}{t} \\\\\\P = \frac{F*d}{t} \\\\\\=> P = F * v$

(where E = energy. t = time taken, d = distance moved)

Force, F, is given as:

F = m*a

Therefore, Power will be:

P = m * a * v

Acceleration, a, will then be:

$a = \frac{P}{m*v}$

$a = \frac{4300}{940 * 118} \\\\\\a = 0.39 m/s^2$

The acceleration of the car at that time is 0.39 $m/s^2$

4 0

3 years ago

Read 2 more answers

What's computer software, give the types of computer software with 5 examples each​

What's computer software, give the types of computer software with 5 examples each