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2 years ago

If a car skids to a stop in 3.8s while undergoing a uniform acceleration of -9.55 m/s2, what is the car’s velocity?

Physics

1 answer:

Lapatulllka [165]2 years ago

3 0

Answer:

36.29 m/s

Explanation:

We know from theory that $v= v_0 +a\Delta t$ . Let's replace the value we know in our equation and solve for the only value left.

$0 = v_0 - 9.55 \cdot 3.8 \\ v_0 = 9.55 \cdot 3.8 = 36.29 m/s$

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Explanation:

Given that,

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(b). We need to calculate the pressure in the nozzle

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$P_{1}+\dfrac{1}{2}\rho\times v_{1}^2+\rho gh_{1}=P_{2}+\dfrac{1}{2}\rho\times v_{2}^2+\rho gh_{2}$

Where, $h_{1}=h_{2}$

$P_{1}+\dfrac{1}{2}\rho\times v_{1}^2=P_{2}+\dfrac{1}{2}\rho\times v_{2}^2$

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Hence, (a).The speed of the water in the nozzle is 3.014 m/s.

(b). The pressure in the nozzle is 1.86 atm.

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