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Vlad1618 [11]
3 years ago
9

How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?

Chemistry
1 answer:
balu736 [363]3 years ago
4 0

The given question is incomplete. The complete question is:

How much heat is produced when 24.8 g of CH_4 is burned in excess oxygen gas

Given: CH _4
+2O_2\rightarrow CO_2+2H_2O  ΔH= −802 kJ.

Answer: 1243.1 kJ

Explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of  1 mole of methane = 802 kJ kJ/mol

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of CH_4 weighs = 16 g  

Thus we can say:  

16 g of CH_4 on combustion releases heat = 802 kJ

Thus 24.8 g of CH_4 on combustion releases =\frac{802}{16}\times 24.8=1243.1kJ

Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ

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An air sample consists of oxygen and nitrogen gas as major components. It also contains carbon dioxide and traces of some rare g
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Explanation:

A mixture is defined as the substance that contains two or more different number of substances that are physically mixed together.

For example, a mixture of air which contains oxygen, nitrogen and other gases.

A mixture in which solute particles are unevenly distributed into the solvent then it is known as a heterogeneous mixture.

For example, sand in water is a heterogeneous mixture.

A homogeneous mixture is defined as the mixture in which solute particles are evenly distributed in a solvent.

A homogeneous mixture is a clear solution.

For example, salt dissolved in water is a homogeneous mixture.

A solution is defined as the substance in which two or more substances are mixed together.

A compound is defined as the substance that contains two or more different elements that chemically combined together in a fixed ratio by mass.

A element is defined as the substance that contains only one type of atoms.

For example, a piece of sodium element will contain only atoms of sodium.

Whereas a pure substance is defined as the substance which contains only one type of molecule or one type of atom.

For example, O_{2}, N_{2} etc are pure substances.

Thus, we can conclude that the terms which could be used to describe the given sample of air is as follows.

  • pure chemical substance.
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4 0
3 years ago
What is the vapor pressure in equilibrium with when the substance has reached its boiling point
S_A_V [24]

Answer:

The boiling point of a liquid is the temperature at which its vapor pressure is equal to the pressure of the gas above it.The normal boiling point of a liquid is the temperature at which its vapor pressure is equal to one atmosphere (760 torr). Microscopic view inside a bubble in boiling water.

Explanation:

8 0
3 years ago
Please Help 8-9!!!!!!!
Airida [17]
Hopefully this will help Im pretty sure this is the answer

3 0
3 years ago
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What determines how the atoms are organized on the periodic table of elements?
tresset_1 [31]
The periodic table of elements arranges all of the known chemical elements in an informative array. Elements are arranged from left to right and top to bottom in order of increasing atomic number. Order generally coincides with increasing atomic mass. The rows are called periods.
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3 years ago
Determine the concentration of a solution prepared by diluting 20.0 mL of 2.00 M NaCl to 250.0 mL. Please show your work.
yawa3891 [41]

0.16 M is the concentration of a solution prepared by diluting 20.0 ml of 2.00 M NaCl to 250.0 ml.

Explanation:

Data given:

Initial volume of NaCl, V1 = 20 ml

initial molarity of the NaCl solution = 2M

Final volume of the NaCl solution = 250 ml

final molarity of the diluted solution = ?

from the information given, the formula for dilution used is:

Minitial Vinitial = Mfinal Vfinal

putting the values in the rearranged equation:

V final = \frac{Minitial Vinitial }{Vfinal}

V final = \frac{20 X 2}{250}

Mfinal = 0.16 M

Thus it can be seen that when a 20 ml solution having molarity of 2M is diluted to 250 ml the molarity decreases to 0.16 M.

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