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valentinak56 [21]
3 years ago
5

How many moles are in 64 grams of methane, CH4? A. 4 B. 32 C. 64 D. 13

Chemistry
1 answer:
ss7ja [257]3 years ago
8 0

Answer:

A. 4.

Explanation:

  • We can use the relation:

<em>no. of moles (n) = mass/molar mass.</em>

mass = 64.0 g, molar mass = 16.0 g/mol.

∴ no. of moles (n) = mass/molar mass = (64.0 g)/(16.0 g/mol) = 4 mol.

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If Log 4 (x) = 12, then log 2 (x / 4) is equal to
Alexus [3.1K]

The value of log₂(x/4) is 22. Using the properties of the logarithm, the required value is calculated.

<h3>What are the required properties of the logarithm?</h3>

The required logarithm properties are

logₐx = n ⇒ aⁿ = x; and logₐ(xⁿ) = n logₐ(x);

Where a is the base of the logarithm.

<h3>Calculation:</h3>

It is given that,

log₄(x) = 12;

On applying the property logₐx = n ⇒ aⁿ = x; here a = 4;

So,

log₄(x) = 12 ⇒ 4¹² = x

⇒ x = (2²)¹² = 2²⁴

Then, calculating log₂(x/4):

log₂(x/4) = log₂(2²⁴/4)

              = log₂(2²⁴/2²)

              = log₂(2²⁴ ⁻ ²)

              = log₂(2²²)

On applying the property logₐ(xⁿ) = n logₐ(x);

log₂(x/4) = 22 log₂2

We know that logₐa = 1;

So,

log₂(x/4) = 22(1)

∴ log₂(x/4) = 22.

Learn more about the properties of logarithm here:

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8 0
2 years ago
Which of the following species has
Kisachek [45]

Answer:

see explanation...

Explanation:

                               Mg⁺²-24                     Co⁺³-60                     Clˉ-35    

Protons (p⁺)                12                                 27                             17              

Neutrons (n⁰)             12                                 33                             18              

Electrons (eˉ)             10                                 24                             18              

                                  (c)                                 (b)                            (a)

                         12/2 : 12/2 : 10/2      27/3 : 33/3 : 24/3        #n⁰ = 18

                             6    :    6   :    5          9  :   11  :   8             #eˉ = 18

7 0
4 years ago
Saftey goggles are worn in the lab- ​
Harrizon [31]

Answer:

Yes

Explanation:

Is this a question or what?

4 0
3 years ago
A pharmaceutical company wants to test the efficiency of its new drug production techniques so they run 3 shifts of production f
spayn [35]

The percentage yield of the  new production technique is 82.8%

<h3>What is the percentage yield?</h3>

Production is the procedure by which finished products are obtained form the raw materials. The production process involves the passing of raw materials through a certain procedure that involves the use of certain machines and equipment to give us the required products.

We are told in the question that there are three shifts;

Shift 1 produces 4562 grams

Shift 2 produces 5783 grams

Shift 3 produces 5247 grams

Average production from the three shifts = 4562 grams + 5783 grams +  5247 grams/3 = 5197 grams

The theoretical average yield is =  7000 grams + 7000 grams + 7000 grams/3 = 7000 grams

Now the percentage yield = actual yield/ theoretical yield * 100/1

percentage yield = 5197 grams/7000 grams * 100/1

percentage yield = 82.8%

Learn more about percentage yield :brainly.com/question/27492865

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3 0
2 years ago
The maximum amount of nickel(II) cyanide that will dissolve in a 0.220 M nickel(II) nitrate solution is...?
sweet [91]

Answer : The maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

Explanation :

The solubility equilibrium reaction will be:

                       Ni(CN)_2\rightleftharpoons Ni^{2+}+2CN^-

Initial conc.                        0.220       0

At eqm.                             (0.220+s)   2s

The expression for solubility constant for this reaction will be,

K_{sp}=[Ni^{2+}][CN^-]^2

Now put all the given values in this expression, we get:

3.0\times 10^{-23}=(0.220+s)\times (2s)^2

s=5.84\times 10^{-12}M

Therefore, the maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

7 0
3 years ago
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