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matrenka [14]
3 years ago
14

How many molecules are in

Chemistry
1 answer:
diamong [38]3 years ago
6 0

Answer:

3.6 × 10²⁴ molecules

Explanation:

Step 1: Given data

Moles of methane (n): 6.0 moles

Step 2: Calculate the number of molecules of methane in 6.0 moles of methane

In order to convert moles to molecules, we need a conversion factor. In this case, we will use Avogadro's number: there are 6.02 × 10²³ molecules of methane in 1 mole of molecules of methane.

6.0 mol × 6.02 × 10²³ molecules/1 mol = 3.6 × 10²⁴ molecules

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quizlet a basement is successfully sealed so that more radon may not enter the space, but 5.7×107 radon atoms are already trappe
12345 [234]

After 25 days, it remains radon 5.9x10^5 atoms.

Half-life is the time required for a quantity (in this example number of radioactive radon) to reduce to half its initial value.

N(Ra) = 5.7×10^7; initial number of radon atoms

t1/2(Ra) = 3.8 days; the half-life of the radon is 3.8 days

n = 25 days / 3.8 days

n = 6.58; number of half-lifes of radon

N1(Ra) = N(Ra) x (1/2)^n

N1(Ra) = 5.7×10^7 x (1/2)^6.58

N1(Ra) = 5.9x10^5; number of radon atoms after 25 days

The half-life is independent of initial concentration (size of the sample).

More about half-life: brainly.com/question/1160651

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6 0
2 years ago
Explain the relationship between mutations, adaptations, natural selection, and extinction.
Masja [62]

Answer:

They all need to use each other to function?

Explanation:

Natural selection are positive traits, mutation is radioactive, and adaption is when natural selection works.

8 0
3 years ago
Read 2 more answers
2H2+ O2 —> 2H2 O
lukranit [14]

Answer:bubuvuvuvftctcrchj

Explanation:

8 0
3 years ago
What type of atom is hydrogen with an atomic mass of 1 and 2 electrons
Charra [1.4K]

Answer:

This would be the hydride ion where H gains an electron from a metal such as  Na

Explanation:

7 0
4 years ago
A laboratory experiment requires 2.25 L of a 1.0 M solution of phosphoric acid (H3PO4), but the only available H3PO4 is a 9.0 M
Ksenya-84 [330]
The solution needed is prepared  as below

by use of the   M1V1 =M2 V2  formula  where
M1 = 2.25 L
v2 = 1.0M
M2 = 9.0 M
V2 =? l

make V2  the subject of the formula  V2 =M1V1/M2

= 2.25 L x  1.0M/9.0 M  = 0. 25 L

therefore  the solution  need  0.25 L  of   9.0M H3PO4   and  dilute it a final volume  of 2.25 l 
6 0
3 years ago
Read 2 more answers
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