Question

A 15.75-g piece of iron absorbs 1086.75 joules of heat energy, and its temperature changes from 25°C to 175°C. What is the specific heat capacity of iron?

Answer 1

Answer:

$0.46 J/g^{\circ}C$

Explanation:

The heat absorbed by the piece of iron is given by:

$Q=m C_s \Delta T$

where here we have

Q = 1086.75 J is the heat absorbed

m = 15.75 g is the mass of the piece of iron

Cs is the iron's specific heat

$\Delta T=175^{\circ}C-25^{\circ} C=150^{\circ}C$ is the change in temperature of the piece of iron

If we re-arrange the formula and we solve for Cs, we find the iron's specific heat capacity:

$C_s=\frac{Q}{m \Delta T}=\frac{1086.75 J}{(15.75 g)(150^{\circ}C)}=0.46 J/gC$